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Sindrei [870]
2 years ago
5

HELP! Write an equation that represents the relationship between the two variables.

Mathematics
1 answer:
vova2212 [387]2 years ago
7 0

Answer:

x + 1, y + 1

Step-by-step explanation:

For every x there is a y

(っ◔◡◔)っ ♥ Hope It Helps ♥

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x . 0.3

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Step-by-step explanation:

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Find the total surface area of the square pyramid in the figure.<br><br> thanks!!
Viefleur [7K]

Answer:

B: 144 yd²

Step-by-step explanation:

It's a square pyramid : Base area 8 x 8 = 64

4 side area:((8 x5) /2) x 4 = 80

Total area: 64 +80 = 144

5 0
3 years ago
The life of a red bulb used in a traffic signal can be modeled using an exponential distribution with an average life of 24 mont
BartSMP [9]

Answer:

See steps below

Step-by-step explanation:

Let X be the random variable that measures the lifespan of a bulb.

If the random variable X is exponentially distributed and X has an average value of 24 month, then its probability density function is

\bf f(x)=\frac{1}{24}e^{-x/24}\;(x\geq 0)

and its cumulative distribution function (CDF) is

\bf P(X\leq t)=\int_{0}^{t} f(x)dx=1-e^{-t/24}

• What is probability that the red bulb will need to be replaced at the first inspection?

The probability that the bulb fails the first year is

\bf P(X\leq 12)=1-e^{-12/24}=1-e^{-0.5}=0.39347

• If the bulb is in good condition at the end of 18 months, what is the probability that the bulb will be in good condition at the end of 24 months?

Let A and B be the events,

A = “The bulb will last at least 24 months”

B = “The bulb will last at least 18 months”

We want to find P(A | B).

By definition P(A | B) = P(A∩B)P(B)

but B⊂A, so  A∩B = B and  

\bf P(A | B) = P(B)P(B) = (P(B))^2

We have  

\bf P(B)=P(X>18)=1-P(X\leq 18)=1-(1-e^{-18/24})=e^{-3/4}=0.47237

hence,

\bf P(A | B)=(P(B))^2=(0.47237)^2=0.22313

• If the signal has six red bulbs, what is the probability that at least one of them needs replacement at the first inspection? Assume distribution of lifetime of each bulb is independent

If the distribution of lifetime of each bulb is independent, then we have here a binomial distribution of six trials with probability of “success” (one bulb needs replacement at the first inspection) p = 0.39347

Now the probability that exactly k bulbs need replacement is

\bf \binom{6}{k}(0.39347)^k(1-0.39347)^{6-k}

<em>Probability that at least one of them needs replacement at the first inspection = 1- probability that none of them needs replacement at the first inspection. </em>

This means that,

<em>Probability that at least one of them needs replacement at the first inspection =  </em>

\bf 1-\binom{6}{0}(0.39347)^0(1-0.39347)^{6}=1-(0.60653)^6=0.95021

5 0
3 years ago
Given that ABCD is a rhombus, what is the value of x?
SashulF [63]

Answer:

B

Step-by-step explanation:

A rhombus is divided into four congruent triangles. The two given angles are complementary, meaning they add up to 90 degrees. Set up an equation:

(4x-25)+x=90

4x-25+x=90   Take out the parentheses

5x-25=90   Combine like terms

5x=115   Add 25 to both sides so as to isolate the variable

x=23   Divide both sides by 5

3 0
3 years ago
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