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Sindrei [870]
2 years ago
5

HELP! Write an equation that represents the relationship between the two variables.

Mathematics
1 answer:
vova2212 [387]2 years ago
7 0

Answer:

x + 1, y + 1

Step-by-step explanation:

For every x there is a y

(っ◔◡◔)っ ♥ Hope It Helps ♥

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Is the square number of 32 a whole number?​
Aneli [31]
No it’s not the square root of 32 is 5.65685424949
4 0
3 years ago
Read 2 more answers
Solve for x.<br><br> 4−(2x+4)=5<br><br> A. x=32<br> B. x=−52<br> C. x=−10<br> D. x = 6
Dennis_Churaev [7]
  • <em>Answer:</em>

<em>x = - 2.5</em>

  • <em>Step-by-step explanation:</em>

<em>Hi there !</em>

<em>4 - (2x + 4) = 5</em>

<em>4 - 2x - 4 = 5</em>

<em>- 2x = 5</em>

<em>2x = - 5</em>

<em>x = - 5 : 2</em>

<em>x = - 2.5</em>

<em>Good luck !</em>

6 0
3 years ago
Somebody please help
pickupchik [31]

Answer:

A.

Step-by-step explanation:

The volume is LWH

L = 16

W = 9

H = 12

16 * 9 * 12 = 1728

4 0
3 years ago
What is 35 x 345? Solve and I will give you money
Otrada [13]

Answer:

12075

Step-by-step explanation:

35 x 345 = 12075

8 0
2 years ago
Read 2 more answers
Someone please be awesome and help me please :(
solong [7]

Answer:

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Step-by-step explanation:

x^2+\frac{b}{a}x+\frac{c}{a}=0

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared.  Whatever you add in, you must take out.

x^2+\frac{b}{a}x+(\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0

Now we are read to write that one part (the first three terms together) as a square:

(x+\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0

I don't see this but what happens if we find a common denominator for those 2 terms after the square.  (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

(x+\frac{b}{2a})^2+\frac{4ac}{4a^2}-\frac{b^2}{4a^2}=0

They put it in ( )

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

I'm going to go ahead and combine those fractions now:

(x+\frac{b}{2a})^2+(\frac{-b^2+4ac}{4a^2})=0

I'm going to factor out a -1 in the second term ( the one in the second ( ) ):

(x+\frac{b}{2a})^2-(\frac{b^2-4ac}{4a^2})=0

Now I'm going to add (b^2-4ac)/(4a^2) on both sides:

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

I'm going to square root both sides to rid of the square on the x+b/(2a) part:

x+\frac{b}{2a}=\pm \sqrt{\frac{b^2-4ac}{4a^2}}

x+\frac{b}{2a}=\pm \frac{\sqrt{b^2-4ac}}{2a}

Now subtract b/(2a) on both sides:

x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Combine the fractions (they have the same denominator):

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

6 0
3 years ago
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