Answer:
y=2x
Step-by-step explanation:
The line passes through the origin, so the y-intercept = 0
the slope m can be found with
m = (y2-y1)/(x2-x1) = (8-2)/(2-1) = 2
Therefore the equation of the line is
y = 2x + 0 = 2x
9514 1404 393
Answer:
2x² +5x -12 = 0
Step-by-step explanation:
When p and q are roots of a quadratic, its factored form can be written as ...
(x -p)(x -q) = 0
Here, the roots are given as -4 and 3/2, so the factored form would be ...
(x -(-4))(x -(3/2) = 0
Multiplying by 2 gives us ...
(x +4)(2x -3) = 0
Expanding the product, we find the desired quadratic is ...
2x² +5x -12 = 0
12 x 12 = 144, 144 x 3 and then subtract 5 to get 427
The height of the fireworks from the ground is f(t) =![-16t^2 + 224t](https://tex.z-dn.net/?f=%20%20-16t%5E2%20%2B%20224t%20)
Given that the fireworks will now be launched from the top of a 120-foot-tall building.
In general, the height function h(t) = –16t^2 + v0t + h0
V0- is the initial velocity, h0 is the initial height
Initial velocit = 224
Initial height = 120
So the new function g(t) = ![-16t^2 + 224t + 120](https://tex.z-dn.net/?f=%20%20-16t%5E2%20%2B%20224t%20%2B%20120%20)
Original function f(t) = ![-16t^2 + 224t](https://tex.z-dn.net/?f=%20%20-16t%5E2%20%2B%20224t%20)
New function g(t)= ![-16t^2 + 224t + 120](https://tex.z-dn.net/?f=%20%20-16t%5E2%20%2B%20224t%20%2B%20120%20)
In original function f(x), the firework is launched from the ground so the initial height is 0.
In new function g(x), the firework is launched from the top of a 120-foot-tall building so the initial height is 120.Hence 120 is added with f(x) to get g(x).
Answer:A unit rate is a rate with 1 in the denominator. If you have a rate, such as price per some number of items, and the quantity in the denominator is not 1, you can calculate unit rate or price per unit by completing the division operation: numerator divided by denominator.
Step-by-step explanation: