Answer:
The probability of a customer buying carrots is 0.10.
Step-by-step explanation:
Here, given:
P (Customer buying apples) = 12%
⇒ P(A) = 12 \100 = 0.12
P(Customer Buying apples AND Carrots) = 5%
⇒ P(A ∩ C ) = 5 /100 = 0.05
P(Customer buying apples OR carrots ) = 17%
⇒ P(A∪ C) = 17/100 = 0.17
Now, we know that:
<h3>
P(X ∪ Y) = P(X) + P(Y) - P(X ∩ Y ) </h3><h3>
</h3>
Now, here substituting the values, we get:
P(A∪ C) = P(A) + P(C) - P(A ∩ C )
⇒ 0. 17 = 0.12 + P(C) - 0.05
or, 0.17 - 0.07 = P(C)
or, P(C) = 0.10
or, P(Customer Buying Carrots) = 0.10
Hence, the probability of a customer buying carrots is 0.10.
Answer:
Can you tell me what they are looking for in the question?
Add up 2, 1 and 3. Result: 6.
Mother received 2 parts out of 6, or (2/6)(18) = 6 apples;
Father rec'd 1 part out of 6, or (1/6)(18) = 3 apples, and Julia herself rec'd (3/6)(18), or 9, apples.
If she can only work 15 hours a week and earns $7 per hour, just multiply 7 by 15 and you'll have your answer :)