What is the volume of a triangle prism that has a height of 45 meters and has a base with an area of 20 square meters

A water company charges a connection fee each month of $22 and an additional $2.30 per cubic foot of water used. Which function

EastWind [94]

Answer

Find out the total monthly charges for x cubic feet of water used .

To prove

As given

A water company charges a connection fee each month of $22 and an additional $2.30 per cubic foot of water used.

Than the equation become

Total monthly charges for x cubic feet of water used = Monthly connection fee + charges for x cubic feet of water

thus

f(x) = 22 + 2.30x

where x is the x cubic feet of water used .

Therefore Option (B) is correct i.e f(x) = 22 + 2.30x .

4 0

2 years ago

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How do you write 7/10 as a decimal Can someone please help me!!

insens350 [35]

Answer:

0.7

Step-by-step explanation:

To get 7/10 as a decimal you simply divide 7 by 10 which gets you 0.7.

7 0

3 years ago

two angles are complementary. the larger angle is 6 more than five times the number. how large is the smaller angle?

spin [16.1K]

Answer:

14 degrees

Step-by-step explanation:

Complementary angles means they add up to 90 degrees.

If the smaller angle times 5 plus 6 equals the bigger angle, then:

14 x 5 = 70

70 + 6 = 76

76 + 14 = 90

6 0

2 years ago

Read 2 more answers

Solve using long division <br> Please

madreJ [45]

1. $Solution,\frac{2x^3+4x^2-5}{x+3}:\quad 2x^2-2x+6-\frac{23}{x+3}$

$Steps:$

$\mathrm{Divide}\:\frac{2x^3+4x^2-5}{x+3}:\quad \frac{2x^3+4x^2-5}{x+3}=2x^2+\frac{-2x^2-5}{x+3}$

$\mathrm{Divide}\:\frac{-2x^2-5}{x+3}:\quad \frac{-2x^2-5}{x+3}=-2x+\frac{6x-5}{x+3}$

$\mathrm{Divide}\:\frac{6x-5}{x+3}:\quad \frac{6x-5}{x+3}=6+\frac{-23}{x+3}$

$\mathrm{Simplify}, =2x^2-2x+6-\frac{23}{x+3}$

$\mathrm{The\:Correct\:Answer\:is\:2x^2-2x+6-\frac{23}{x+3}}$

2. $Solution, \frac{4x^3-2x^2-3}{2x^2-1}:\quad 2x-1+\frac{2x-4}{2x^2-1}$

$Steps:$

$\mathrm{Divide}\:\frac{4x^3-2x^2-3}{2x^2-1}:\quad \frac{4x^3-2x^2-3}{2x^2-1}=2x+\frac{-2x^2+2x-3}{2x^2-1}$

$\mathrm{Divide}\:\frac{-2x^2+2x-3}{2x^2-1}:\quad \frac{-2x^2+2x-3}{2x^2-1}=-1+\frac{2x-4}{2x^2-1}$

$\mathrm{The\:Correct\:Answer\:is\:2x-1+\frac{2x-4}{2x^2-1}}$

$\mathrm{Hope\:This\:Helps!!!}$

$\mathrm{-Austint1414}$

4 0

3 years ago

Please please please help. thank you.

djverab [1.8K]

Lets get started :)

The First question:
Diameter = 20 ft
Radius = $\frac{1}{2}$ of 20 (diameter) = 20 ft

Area formula of a circle is
A = $\pi$ r²
= $\pi$ (10)²
=100 $\pi$ ft²
≈ 314 ft²

The answer will be the second option

The Second question:
radius of circle = 12mm divided into 20 sectors area

A = $\pi$ r²
= $\pi$ (12)²
= 144 $\pi$ ft²

Divide into 20 equal sector areas = $\frac{144 \pi }{20} = 7.2 \pi$

≈ 22.6 mm²

Your answer will be the third option

The Third Question:

90°, sector area = 36 $\pi$ , Radius = ?

$\frac{angle}{360} = \frac{sector}{ \pi (r)^2}$
$\frac{90}{360} = \frac{36 \pi }{ \pi r^2}$
$\pi$ and $\pi$ cancels out

We can now cross multiply
360 × 36 = 90r²
12960 = 90r²

Divide by 90 on either side

$\frac{12960}{90} = \frac{90r^2}{90}$
144 = r²

Take squareroot
$\sqrt{144} = x$
x = 12 in

Your answer will be the third option

4 0

3 years ago