Answer:
3.17mol
Explanation:
moles of Na = m/M ; Where M - molar mass of Na which is 23
moles of Na = 73/23 =3.17mol
but from the eqn n(Na) : n(NaOH) = 2:2 = 1:1
: . moles of NaOH is also 3.17mol
The answer is A mutualism
Answer:
50000 dollars or 5 e5
Explanation:
Mr. Garibay has 
dollars in his bank.
Scientific notation represents the data in the format of expanded number or with e character.
For instance, 5.0 * 10^4 dollars = 50000 dollars or 5 e5
Boron:atomic number-5,valency-+3,atomic mass- 11amu
MNaHCO₃: 23+1+12+(48×3) = 84g
mCH₃COOH: 12+(1×3)+12+(16×2)+1 = 60g
.................
84g NaHCO₃ react with 60g CH₃COOH
83g NaHCO₃ react with...........
84g ----- 60g
83g ----- X
X = 59,29g CH₃COOH
We used 70g CH₃COOH, it' too much.
So, acetic acid is excess reagent, and sodium bicarbonate is limiting reagent.
_______________________________
B) Amount of CH3COOH is in excess.
:•)
