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3 years ago

What type of energy does a rock resting on top of the hill have?

Chemistry

2 answers:

fomenos3 years ago

5 0

The answer is C potential energy, hope this helps :)

GenaCL600 [577]3 years ago

4 0

C is the answer to the problem

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A 75 um thick polysulphone microporous membrane has an average porosity of E 0.35. Pure water flux through the membrane is 35 m'

Paul [167]

Explanation:

The given data is as follows.

Water flux, $J_{w}$ = 25 $m^{3}/m^{2}h$

= $\frac{25}{3600} m^{3}/m^{2}h$

So, let velocity (u) = $\frac{25}{3600}$ m/s = $6.9 \times 10^{-3}$

$\rho$ = 998 $kg/m^{3}$

Pore size, d = $0.8 \times 10^{-6} m$

$\mu$ = 0.9 cP = $9 \times 10^{-4}$ Pa.s

Hence, calculate the reynold number as follows.

$R_{e} = \frac{\rho \times u \times d}{\mu}$

= $\frac{998 kg/m^{3} \times 6.9 \times 10^{-3} \times 0.8 \times 10^{-6} m}{9 \times 10^{-4} Pa.s}$

= $612.1 \times 10^{-5}$

= 0.006

This means that the flow is laminar.

Now, we use Hagen-Poiseuille equation as follows.

$J_{w} = \frac{\varepsilon \times d^{2}}{32 \times \mu \times \tau} \times \frac{\Delta P}{L_{m}}$

where, $\varepsilon$ = membrane porosity = 0.35

d = $0.8 \times 10^{-6}$ m

$\Delta P$ = $2 \times 10^{5} Pa$

$\mu$ = $9 \times 10^{-4}$

$\tau$ = tortuosity

$L_{m}$ = membrane thickness = $75 \times 10^{-6} m$

$\frac{25}{3600} = \frac{0.35 \times (0.8 \times 10^{-6})}{32 \times (9 \times 10^{-4}) \times \tau}$

$\tau$ = 3.73

Hence, the tortuosity factor of the pores is 3.73.

As flow resistance = $R_{m}$

$J_{w} = \frac{\Delta P}{r \times R_{m}}$

$R_{m} = 3.2 \times 10^{10} m^{-1}$

Water permeability is represented by $L_{p}$ .

$J_{w} = L_{p} \times \Delta P$

$6.9 \times 10^{-3}$ = $L_{p} \times 2 \times 10^{5} Pa$

$L_{p} = 3.45 \times 10^{-8} m^{3}/m^{2}s Pa$

Therefore, the resistance to flow is $3.2 \times 10^{10} m^{-1}$ and its water permeability is $3.45 \times 10^{-8} m^{3}/m^{2}s Pa$ .

3 0

3 years ago

What is the weight of a 90kg man standing on Earth, where gᵉᵃʳᵗʰ = 9.82 m/s^2?

Ray Of Light [21]

Answer:

$88.38 Kgm/s^2$

Explanation:

Mass and weight are quite different terms .

Weight is defined as the amount of force exerted on the earth due to our mass and gravity of acceleration.

$W=m*g$

Given that the mass is 90 kg and gravity of acceleration of earth is 9.82 m/s^2.

So weight will be

$W=90*9.82\\\\ W=88.38 Kgm/s^2$

So this is the weight of the 90kg man standing on earth.

7 0

3 years ago

Will mark BRAINLIEST!

Nataliya [291]

Answer:

Explanation:

2 NO2(g) ⇄ N2O4(g)

Adding Argon to this reaction will have NO effect. Catalysts nor inert gases have an affect on equilibrium conditions.

Only changes in concentration, temperature conditions and pressure-volume conditions (unless both sides have equal molar volumes) will affect the equilibria.

NH4OH(aq) ⇄ NH3(g) + H2O(l)

Removing ammonia from reaction equilibrium causes the reaction to shift right to replace removed ammonia. => Think of the reaction as being on a seesaw => removing ammonia from the product side tilts the seesaw left causing the NH₄OH to decompose and deliver more NH₃ and H₂O to the product side to increase weight on that side and level the seesaw. :-)

5 0

3 years ago

What graph would you use if you wanted to compare similar data for several individual items or events?

Soloha48 [4]

Answer:

A. Bar graph

Explanation:

Bar graphs are used to compare things between different groups or to track changes over time.

5 0

2 years ago

Read 2 more answers

10. Which of these measurements have four significant figures? *

anastassius [24]

Answer:

3.050 g

Explanation:

6 0

4 years ago