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Anettt [7]
4 years ago
14

What are the discontinues of the function f(x) = x^2 - 16/6x-24

Mathematics
1 answer:
Mumz [18]4 years ago
3 0
The function f(x) = (x^2 - 16) / (6x - 24) is discontinuos at
6x - 24 = 0
6x = 24
x = 4.
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Try this option:
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3 years ago
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