All categories

4 years ago

What are the discontinues of the function f(x) = x^2 - 16/6x-24

Mathematics

1 answer:

Mumz [18]4 years ago

3 0

The function f(x) = (x^2 - 16) / (6x - 24) is discontinuos at
6x - 24 = 0
6x = 24
x = 4.

You might be interested in

The area of a trapezium is 34 cm and the length one of its parallel side is

Natasha_Volkova [10]

Answer:

6.6 cm.

Step-by-step explanation:

The area of a trapezium A = (h/2)(a + b) where h = the height, a and b are the length of the parallel sides.

So substituting the given values in this formula:

34 = (4/2)(10.4 + b)

34 = 2(10.4 + b

34 = 20.8 + 2b

2b = 34 - 20.8 = 13.2

b = 6.6 cm.

3 0

3 years ago

Trey rented a truck for one day. There was a base fee of $20.99, and there was an additional charge of .96 cents for each mile d

coldgirl [10]

Answer:

He drove the truck for 234 miles

Step-by-step explanation:

Let x represent the number of miles for which he drove the truck.

There was a base fee of $20.99, and there was an additional charge of .96 cents for each mile driven. It means that the expression for the cost of driving the truck for x miles in a day is

20.99 + 0.96x

Trey has to pay $245.63 when he returned the truck. It means that

20.99 + 0.96x = 245.63

0.96x = 245.63 - 20.99

0.96x = 224.64

x = 224.64/0.96

x = 234 miles

8 0

3 years ago

Which graph correctly solves the system of equations below?

trapecia [35]

Combine like terms: y=5x+4 and y=4x+1. Sub one in: 4x+1=5x+4. -1x=3. X=-3. Sub into other one: y=4•-3+1. Y=-12+1. Y=-11. Check it: -11=5•-3+4. -11=-15+4. -11=-11. So X=-3 and Y=-11 :)

4 0

4 years ago

What will be the value of

madreJ [45]

The expression as given doesn't make much sense. I think you're trying to describe an infinitely nested radical. We can express this recursively by

$\begin{cases}a_1=\sqrt{42}\\a_n=\sqrt{42+a_{n-1}}\end{cases}$

Then you want to know the value of

$\displaystyle\lim_{n\to\infty}a_n$

if it exists.

To show the limit exists and that $a_n$ converges to some limit, we can try showing that the sequence is bounded and monotonic.

Boundedness: It's true that $a_1=\sqrt{42}\le\sqrt{49}=7$ . Suppose $a_k\le 7$ . Then $a_{k+1}=\sqrt{42+a_k}\le\sqrt{42+7}=7$ . So by induction, $a_n$ is bounded above by 7 for all $n$ .

Monontonicity: We have $a_1=\sqrt{42}$ and $a_2=\sqrt{42+\sqrt{42}}$ . It should be quite clear that $a_2>a_1$ . Suppose $a_k>a_{k-1}$ . Then $a_{k+1}=\sqrt{42+a_k}>\sqrt{42+a_{k-1}}=a_k$ . So by induction, $a_n$ is monotonically increasing.