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fiasKO [112]
3 years ago
14

Which example is the best demonstration of initiative?

Computers and Technology
1 answer:
alisha [4.7K]3 years ago
4 0

Answer: In this context, the best answer for the given questions would be (B) you offer to take on some extra work when a coworker is out sick.

Explanation: Initiative is pretty much defined as an action that is taken independently by someone. It could be said that one person with an initiative does not need someone else to tell him/her to do something.

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Create a macro named mReadInt that reads a 16- or 32-bit signed integer from standard input and returns the value in an argument
timofeeve [1]

Answer:

;Macro mReadInt definition, which take two parameters

;one is the variable to save the number and other is the length

;of the number to read (2 for 16 bit and 4 for 32 bit) .

%macro mReadInt 2

mov eax,%2

cmp eax, "4"

je read2

cmp eax, "2"

je read1

read1:

mReadInt16 %1

cmp eax, "2"

je exitm

read2:

mReadInt32 %1

exitm:

xor eax, eax

%endmacro

;macro to read the 16 bit number, parameter is number variable

%macro mReadInt16 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;macro to read the 32 bit number, parameter is number variable

%macro mReadInt32 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;program to test the macro.

;data section, defining the user messages and lenths

section .data

userMsg db 'Please enter the 32 bit number: '

lenUserMsg equ $-userMsg

userMsg1 db 'Please enter the 16 bit number: '

lenUserMsg1 equ $-userMsg1

dispMsg db 'You have entered: '

lenDispMsg equ $-dispMsg

;.bss section to declare variables

section .bss

;num to read 32 bit number and num1 to rad 16-bit number

num resb 5

num1 resb 3

;.text section

section .text

;program start instruction

global _start

_start:

;Displaying the message to enter 32bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg

mov edx, lenUserMsg

int 80h

;calling the micro to read the number

mReadInt num, 4

;Printing the display message

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Printing the 32-bit number

mov eax, 4

mov ebx, 1

mov ecx, num

mov edx, 4

int 80h

;displaying message to enter the 16 bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg1

mov edx, lenUserMsg1

int 80h

;macro call to read 16 bit number and to assign that number to num1

;mReadInt num1,2

;calling the display mesage function

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Displaying the 16-bit number

mov eax, 4

mov ebx, 1

mov ecx, num1

mov edx, 2

int 80h

;exit from the loop

mov eax, 1

mov ebx, 0

int 80h

Explanation:

For an assembly code/language that has the conditions given in the question, the program that tests the macro, passing it operands of various sizes is given below;

;Macro mReadInt definition, which take two parameters

;one is the variable to save the number and other is the length

;of the number to read (2 for 16 bit and 4 for 32 bit) .

%macro mReadInt 2

mov eax,%2

cmp eax, "4"

je read2

cmp eax, "2"

je read1

read1:

mReadInt16 %1

cmp eax, "2"

je exitm

read2:

mReadInt32 %1

exitm:

xor eax, eax

%endmacro

;macro to read the 16 bit number, parameter is number variable

%macro mReadInt16 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;macro to read the 32 bit number, parameter is number variable

%macro mReadInt32 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;program to test the macro.

;data section, defining the user messages and lenths

section .data

userMsg db 'Please enter the 32 bit number: '

lenUserMsg equ $-userMsg

userMsg1 db 'Please enter the 16 bit number: '

lenUserMsg1 equ $-userMsg1

dispMsg db 'You have entered: '

lenDispMsg equ $-dispMsg

;.bss section to declare variables

section .bss

;num to read 32 bit number and num1 to rad 16-bit number

num resb 5

num1 resb 3

;.text section

section .text

;program start instruction

global _start

_start:

;Displaying the message to enter 32bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg

mov edx, lenUserMsg

int 80h

;calling the micro to read the number

mReadInt num, 4

;Printing the display message

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Printing the 32-bit number

mov eax, 4

mov ebx, 1

mov ecx, num

mov edx, 4

int 80h

;displaying message to enter the 16 bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg1

mov edx, lenUserMsg1

int 80h

;macro call to read 16 bit number and to assign that number to num1

;mReadInt num1,2

;calling the display mesage function

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Displaying the 16-bit number

mov eax, 4

mov ebx, 1

mov ecx, num1

mov edx, 2

int 80h

;exit from the loop

mov eax, 1

mov ebx, 0

int 80h

7 0
3 years ago
How do I write this code in java? input "Enter Your Age to Order a Beer"
Klio2033 [76]

Answer:

i dont know sorry but answer above lol

Explanation:

5 0
3 years ago
What is the purpose of the property, transition-timing-function?
oksano4ka [1.4K]

Answer:

It changes the speed at different stages of the transition.

Explanation:

HTML is an acronym for hypertext markup language and it is a standard programming language which is used for designing, developing and creating web pages.

Generally, all HTML documents are divided into two (2) main parts; body and head. The head contains information such as version of HTML, title of a page, metadata, link to custom favicons and CSS etc. The body of the HTML document contains the contents or informations that a web page displays.

Basically, the purpose of the property, transition-timing-function is that It changes the speed at different stages of the transition. Thus, it states the values between the beginning and ending of a transition are calculated over its duration.

4 0
3 years ago
Explain: The decode part of fetch decode execute cycle
egoroff_w [7]

Answer:

Image below

Explanation:

5 0
3 years ago
Read 2 more answers
Clunker Motors Inc. is recalling all vehicles in its Extravagant line from model years 1999-2002 as well all vehicles in its Guz
Aleksandr [31]

Answer:

The following code is written in java programming language:

//set if statement

if (((modelYear >= 1999) && (modelYear <= 2002) && (modelName == "Extravagant")) || ((modelYear >= 2004) && (modelYear <= 2007) && (modelName == "Guzzler")))

{

recalled = true;    //initialized Boolean value

}

else      //set else statement

{

recalled = false; ////initialized Boolean value

}

Explanation:

Here, we set the if statement and set condition, if the value of modelYear is greater than equal to 1999 and less that equal to 2002 and modelName is equal to "Extravagant" or the value of modelYear is greater than equal to 2004 and less than equal to 2007 and the model year is equal to "Guzzler", than "recalled" initialized to "true".

Otherwise "recalled" initialized to "true".

5 0
3 years ago
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