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3 years ago

Write the name of the tab, command group, and icon you need to use to access the borders and shading dialog box.

Computers and Technology

1 answer:

Ilia_Sergeevich [38]3 years ago

7 0

Answer:

Tab: Home Tab

Command group: Paragraph

Icon: Triangle

Explanation:

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90 POINTS Hazel is working with a database to help determine if the company she works for is making or losing money. Hazel has o

VikaD [51]

Answer:

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2 years ago

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It takes 2 seconds to read or write one block from/to disk and it also takes 1 second of CPU time to merge one block of records.

Alexxx [7]

Answer:

Part a: For optimal 4-way merging, initiate with one dummy run of size 0 and merge this with the 3 smallest runs. Than merge the result to the remaining 3 runs to get a merged run of length 6000 records.

Part b: The optimal 4-way merging takes about 249 seconds.

Explanation:

The complete question is missing while searching for the question online, a similar question is found which is solved as below:

Part a

For optimal 4-way merging, we need one dummy run with size 0.

Merge 4 runs with size 0, 500, 800, and 1000 to produce a run with a run length of 2300. The new run length is calculated as follows $L_{mrg}=L_0+L_1+L_2+L_3=0+500+800+1000=2300$
Merge the run as made in step 1 with the remaining 3 runs bearing length 1000, 1200, 1500. The merged run length is 6000 and is calculated as follows

$L_{merged}=L_{mrg}+L_4+L_5+L_6=2300+1000+1200+1500=6000$

The resulting run has length 6000 records.

Part b

For step 1

Input Output Time

Input Output Time is given as

$T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\, block}$

Here

L_run is 2300 for step 01
Size_block is 100 as given
Time_{I/O per block} is 2 sec

$T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\, block}\\T_{I.O}=\frac{2300}{100} \times 2 sec\\T_{I.O}=46 sec$

So the input/output time is 46 seconds for step 01.

CPU Time

CPU Time is given as

$T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\, block}$

Here

L_run is 2300 for step 01
Size_block is 100 as given
Time_{CPU per block} is 1 sec

$T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\, block}\\T_{CPU}=\frac{2300}{100} \times 1 sec\\T_{CPU}=23 sec$

So the CPU time is 23 seconds for step 01.

Total time in step 01

$T_{step-01}=T_{I.O}+T_{CPU}\\T_{step-01}=46+23\\T_{step-01}=69 sec\\$

Total time in step 01 is 69 seconds.

For step 2

Input Output Time

Input Output Time is given as

$T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\, block}$

Here

L_run is 6000 for step 02
Size_block is 100 as given
Time_{I/O per block} is 2 sec

$T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\, block}\\T_{I.O}=\frac{6000}{100} \times 2 sec\\T_{I.O}=120 sec$

So the input/output time is 120 seconds for step 02.

CPU Time

CPU Time is given as

$T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\, block}$

Here

L_run is 6000 for step 02
Size_block is 100 as given
Time_{CPU per block} is 1 sec

$T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\, block}\\T_{CPU}=\frac{6000}{100} \times 1 sec\\T_{CPU}=60 sec$

So the CPU time is 60 seconds for step 02.

Total time in step 02

$T_{step-02}=T_{I.O}+T_{CPU}\\T_{step-02}=120+60\\T_{step-02}=180 sec\\$

Total time in step 02 is 180 seconds

Merging Time (Total)

Now the total time for merging is given as

$T_{merge}=T_{step-01}+T_{step-02}\\T_{merge}=69+180\\T_{merge}=249 sec\\$

Total time in merging is 249 seconds seconds

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3 years ago

Consider the code below. Note that the catch statements in the code are not implemented, but you will not need those details. As

Dmitriy789 [7]

Missing Part of Question

An exception raised by the instruction in i3 would be caught by the catch statement labeled?

Answer:

e3 and e4.

Explanation:

The instruction tag i3 points to the following code segment

a[++i] = (double) (1 / x); // i3

The code segment above performs arithmetic operation (double)(1/x)

And then assigns the value of the arithmetic operations to an array element a[++I]

It's possible to have one or both of the following two exceptions.

1. Error in Arithmetic Operation

2. Index of Array out of bound

These are both represented in exception tags e3 and e4

catch (ArithmeticException ex) {...} // e3

catch (ArrayIndexOutOfBounds ex) {...} // e4

Exception e3 can arise when the program try to carry out invalid arithmetic operation.

For instance, 1/0 or 0/0.

This will lead to ArithmeticException to be thrown

Exception e4 can arise when the program tries to assign values to an index that's not in an array.

Say, the total index in a given array a is 5.

The index of this array is 0 to 4; i.e. a[0] to a[4]

The moment the program tries to assign values to array element other than the ones I listed above (e.g a[5]) ArrayIndexOutOfBounds exception will be thrown

6 0

3 years ago

For the description below, develop an E-R diagram:

xeze [42]

Answer:

See explaination

Explanation:

E-R diagram:

Entity Relationship Diagram, also known as ERD, ER Diagram or ER model, is a type of structural diagram for use in database design. An ERD contains different symbols and connectors that visualize two important information: The major entities within the system scope, and the inter-relationships among these entities.

Please kindly check attachment for for the ERD of the question asked.

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3 years ago

How many digits are in the binary number system? Explain why.

Katen [24]

Answer:

Since there are only two digits in binary, there are only two possible outcomes of each partial multiplication: If the digit in B is 0, the partial product is also 0. If the digit in B is 1, the partial product is equal to A.

Explanation:

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2 years ago

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