Answer:
x²-3x+2=0
x²-2x-x+2=0
(x²-2x)(-x+2)=0
x(x-2)-1(x-2)=0
(x-2)(x-1)=0
x-2=0 or x-1=0
x=2 or x=1
Since there is one value of y for every value of x in (−4,8),(−2,4),(0,1),(2,4), ( 4,8), this relation is a function. The relation is a function.
30
Step-by-step explanation:
The correct answer should be :
Option 3 :
Hope this helps,
Davinia.