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DerKrebs [107]
3 years ago
8

Write a decimal expression that has the same value as 2.5 divided .5-1.4

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
7 0
<span><span>Dividing decimals by decimals - Homeschool Math</span> go to this</span>
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8/2(2+2)=?<br><br> 100 points to the best answer!
Effectus [21]

Answer:

16

Step-by-step explanation:

8/2(2+2)

- According to the rules of BEDMAS, solve the values inside the bracket.

8/2 (4)

- Simplify the fraction outside the bracket.

4(4)

- Multiply the two values.

= 16

7 0
3 years ago
Read 2 more answers
What is the oblique asymptote of the function f(x) = the quantity x squared minus 5x plus 6 over the quantity x minus 4?
Paraphin [41]

Answer:

x - 1

Step-by-step explanation:

We know that, a slant or oblique asymptote of a rational function is the asymptote that helps in determining the direction of the function.

It occurs when the polynomial in the numerator is a higher degree than the polynomial in the denominator.

Now, we divide the numerator by denominator using long division method and the first two terms in the quotient ( forming a linear function ) is the equation of the oblique asymptote.

We are given the rational function, f(x) = \frac{x^{2}-5x+6}{x-4}.

After dividing we get that, the quotient is x - 1.

Hence, the equation of the oblique asymptote is x-1.

4 0
4 years ago
Find c.<br> Round to the nearest tenth.
solmaris [256]

Answer: Picture is blury for me I can not see it well enough

Step-by-step explanation:

All i see is the 8 ft and 17ft cant see any of the other numbers

8 0
3 years ago
Evaluate the six trigonometric functions of the angle 0.
Arturiano [62]

Given:

Right triangle

To find:

The six trigonometric functions of θ

Solution:

Hypotenuse = 18

Adjacent side to θ = 10

Opposite side to θ = ?

Using Pythagoras theorem:

\text {Hypotenuse}^2 = \text{adjacent}^2+\text{opposite}^2

18^2 =10^2+\text{opposite}^2

324=100+\text{opposite}^2

Subtract 100 from both sides.

224=\text{opposite}^2

Taking square root on both sides.

4\sqrt{14}=\text{opposite}

Using trigonometric ratio formula:

$\sin\theta =\frac{\text{opposite }}{\text{hypotenuse}}

$\sin\theta =\frac{4\sqrt{14} }{18}

$\csc\theta =\frac{\text{hypotenuse}}{\text{opposite }}

$\csc\theta =\frac{18}{4\sqrt{14} }

$\cos \theta=\frac{\text { adjacent side }}{\text { hypotenuse }}

$\cos \theta=\frac{10}{18}

$\sec \theta=\frac{\text { hypotenuse }}{\text { adjacent side }}

$\sec \theta=\frac{18 }{10}

$\tan \theta=\frac{\text { opposite side }}{\text { adjacent side }}

$\tan \theta=\frac{4\sqrt{14} }{10}

$\cot \theta=\frac{\text { adjacent side }}{\text { opposite side }}

$\cot \theta=\frac{10}{4\sqrt{14} }

8 0
3 years ago
Please help I will give you 20 points
zheka24 [161]
You good ?????????????
7 0
3 years ago
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