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kykrilka [37]
2 years ago
12

25. Find the sum of (8p2-2p + 15) and (11 – 2p2 – 1).

Mathematics
2 answers:
umka21 [38]2 years ago
7 0
You need to combine the like terms and put into correct order :)

Vlad [161]2 years ago
6 0

<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>:</em><em>)</em>

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Find the number that makes 4:12 equivalent to 28:__.
guapka [62]

Answer:

84

Step-by-step explanation:

We can set up a proportion using fractions.

\frac{4}{12} = \frac{28}{x}

Now, let's cross multiply by multiplying 12 and 28 then dividing by 4.

12\cdot28=336\\\\336\div4=84

Hope this helped!

6 0
3 years ago
Read 2 more answers
Suppose a NBA basketball player has 5% chance of picking up a foul every minute he plays. What is the probability that he will p
alukav5142 [94]

Answer:

He wont foul out with probability 0.9093

Step-by-step explanation:

The total number of fools he picked is a Binomial ditribution noted by X with parameters p = 0.05 and N = 48. The mean of this random variable is μ = np = 48*0.05 = 2.4 and the variance is σ² = np(1-p) = 2.4*0.95 = 2.28, hence its standard deviation is σ = √2.28 = 1.51.

Note that, if approximate probability is asked, we could just approximate X with a Normal random variable with mean 2.4 and standard deviation 1.51 (this can be done because of the central limit theorem). We will calculate the probability manually. He wont foul out if he picks 0,1,2,3 or 4 fouls, thus

P(X \leq 4) = P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4) \\= 0.95^{48}+48*0.95^{47}*0.05+{48 \choose 2}*0.95^{46}*0.05^2+\\{48 \choose 3}*0.95^{45}*0.05^3+{48 \choose 4}*0.95^{44}*0.05^4 \\= 0.085+0.215+0.266+0.215+0.127 = 0.9093

As a consecuence, he wont foul out with probability 0.9093.

8 0
3 years ago
At the Grassy Meadows Mennonite School, the total number of students in grade 7-9 is the lowest commom multiple of the numbers o
kobusy [5.1K]

Answer:

Seven  

Step-by-step explanation:

Let G7, G8, and G9 be the numbers of students in the respective grades.

Then, G7 + G8 + G9 = LCM of G8 and G9

<em>Data: </em>

G8 = 5

G9 = 3

<em>Calculations: </em>

<em>Multiples of 5</em>: 1 2          10 15

<em>Multiples of 3</em>: 1   3 6 9       15

The <em>LCM</em> of 5 and 3 is 15.

G7 + 5 + 3 = 15     Combine like terms

     G7 + 8 = 15     Subtract 8 from each side

           G7 = 7

There are seven students in Grade 7.


4 0
3 years ago
12 - 3/4 (d + 16) = negative 5
Nutka1998 [239]

Answer: d=20/3

Step By Step:

Step 1, Simplify:

12-3/4(d+16)=-5

(-3/4)d+(12-12)=-5

(-3/4)d=-5

Step 2, Multiply each side by 4/(-3)

(4/-3)*(-3/4)d=(4/-3)*-5

d=20/3

8 0
3 years ago
Read 2 more answers
A coin collection is made up of 34 coins comprised of nickels and dimes. The total value of the collection is $1.90. How many di
riadik2000 [5.3K]

Answer:

x = nickels

y= dimes

x + y = 34

.05x + .10y= $1.90

-.10x - .10y = -3.40

-.05x + .10y = 1.90

-.05x = -1.50

x = 30 nickels

30 + y = 34

y = 4 dimes

(3,4)

7 0
3 years ago
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