The answer is : x= -y/3+2
Area of Shaded triangle as a whole: 136cm^2
Area of Rectangle 1 : 20cm^2
Area of Rectangle 2 : 6cm ^ 2
Area of the shaded region :
136 - (20+6)
136 - (26)
110 cm^2
Answer:
- table: 14, 16, 18
- equation: P = 2n +12
Step-by-step explanation:
Perimeter values will be ...
rectangles . . . perimeter
1 . . . 14
2 . . . 16
3 . . . 18
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The perimeter of a figure is twice the sum of the length and width. Here, the length is a constant 6. The width is n, the number of rectangles. So, the perimeter is ...
P = 2(6 +n) = 12 +2n
Your equation is ...
P = 2n +12 . . . . . . . . perimeter P of figure with n rectangles.
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<em>Additional comment</em>
You may be expected to write the equation using y and x for the perimeter and the number of rectangles. That would be ...
y = 2x +12 . . . . . . . . . perimeter y of figure with x rectangles
