0.424 rounded to nearest tenth would be 0.4 as you can not round up because the hundredth place is not 5 or higher
2 number are x and y
X=10,y=65
<span>it all looks confusing when we try to juggle with all those numbers in the head. The problem can be solved systematically by constructing a contingency table.
</span>role/gender B G total
speaking...... 4 4 8
<span> silent............ 4 8 12
total............. 8 12 20
</span>Probability of a child having a speaking part is therefore
(4+4)/20=8/20=2/5
a. 2/5
Answer:
There is no change.
Step-by-step explanation:
Answer:
i)16
ii)9
Step-by-step explanation:
![\sqrt{256} \\=\sqrt{16*16} \\=16\\\\ii)\ \sqrt[3]{729}\\ =\sqrt[3]{9*9*9} \\=9](https://tex.z-dn.net/?f=%5Csqrt%7B256%7D%20%5C%5C%3D%5Csqrt%7B16%2A16%7D%20%5C%5C%3D16%5C%5C%5C%5Cii%29%5C%20%5Csqrt%5B3%5D%7B729%7D%5C%5C%20%3D%5Csqrt%5B3%5D%7B9%2A9%2A9%7D%20%5C%5C%3D9)