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sergey [27]
3 years ago
5

Use repeated subtraction to divide 35/4

Mathematics
2 answers:
lana [24]3 years ago
7 0

8.75 is the answer rrrrrr
ludmilkaskok [199]3 years ago
3 0

Answer: 8.75

Step-by-step explanation: {35/4} = 35 divided into 4 = 8 remainder 3 that is {35-32}. 3/4 add 0 to 3 (put a decimal) {30/4} = 7 remainder 2 that is {30-28}. add 0 to 2, {20/4} = 5.

Answer 8.75

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7 0
2 years ago
Twice the difference of a number and 3 is at most 27
kozerog [31]

Twice the difference of a number and 3 is at most 27

2*(n-3) <=27


to solve

distribute

2n -6 <=27

add 6 to each side

2n <=33

divide by 2

n <=33/2

n<= 16 1/2


6 0
3 years ago
Milene é doceira e a seguir está uma representação dos bombons que ela fez no dia. Do total dos bombons que fez 2/3 são de coco.
Paha777 [63]

Answer:

16 bombons de coco

Step-by-step explanation:

A partir da pergunta, somos instruídos a fingir que o número total de bombons (chocolate) que ela fez = 24 bombons

Do total de chocolates que ele fez, 2/3 são de coco.

Portanto, a quantidade que representa os doces de coco é representada como:

2/3 × 24

= 16

Portanto, a quantidade de bombons de coco = 16

4 0
3 years ago
Complete the table for the given rule.
lions [1.4K]

The table is

x | 4 | 8 | 12
y |  1 | 2 | 3

The question is not understandable. The well-formatted question is

Complete the table for the given rule

Rule:

y=\dfrac{1}{4}x

Table:

x | 4 | 8 | 12
y |  ? | ? | ?

 

Evaluation of an algebraic expression when a specified integer is used to replace a variable is known as evaluating the expression. We use the provided number to replace the expression's variable before applying the sequence of operations to simplify the expression.

For instance

On evaluation of y= x+7  when x=3, and x=12

we get y(3) = 3 + 7 = 10 and y(12) = 12 + 7 = 19

The given equation is

y=\dfrac{1}{4}x

So, the table is

x | 4 | 8 | 12
y |  1 | 2 | 3

Learn more about evaluation here-

brainly.com/question/14677373

#SPJ10

8 0
2 years ago
Can I get some help plz
saul85 [17]
The line y=-x-3 begins in Q II and ends in Q IV.  Since you have the "equal to or greater than" operator, the shaded area is ABOVE this line, and the line itself is dark (shaded) because of the "equal to."

4 0
3 years ago
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