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Alchen [17]
3 years ago
8

This diagram shows the shape of Lin’s backyard. Which term correctly describes the backyard? A. regular polygon B. hexagon C. pe

ntagon D. quadrilateral

Mathematics
2 answers:
kotegsom [21]3 years ago
6 0

Answer: D quadrilateral

Step-by-step explanation:

Hope this helped.

bekas [8.4K]3 years ago
6 0

Answer: I believe this is D; Quadrilateral

Step-by-step explanation: I saw that this shape is not a regular polygon, hexagon, or pentagon. I saw that this figure contained two sets of quadrilaterals- A trapezoid and a square.

Hope I helped you out <3

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For Mr.Greene's wireless phone bill, 3 months costs $180. For 9 months, his Bill was $540. Which equation best represents the re
Ivenika [448]

Answer:

Very simply divide the 3 months cost, $180, by 3.

180/3 = 60

y = 60x

7 0
4 years ago
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Classify the triangle as acute, obtuse, or right if it has sides of 10, 12, and 15.
Alexandra [31]

Answer:

acute triangle

Step-by-step explanation:

3 0
3 years ago
...yea i just need help (:
dsp73

Answer:

2/3-4

3 1/3

-1*3.3=-3.3

-3 1/3 divided by 5/6

-4

so a

Hope This Helps!!!

3 0
3 years ago
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Fill in each blank for the function f(x) = 3x - 6.
IRINA_888 [86]

Answer:

reeee :(

Step-by-step explanation:

7 0
3 years ago
I think I know this much so far for A (but I could be wrong):
Eduardwww [97]
Part A. You have the correct first and second derivative.

---------------------------------------------------------------------

Part B. You'll need to be more specific. What I would do is show how the quantity (-2x+1)^4 is always nonnegative. This is because x^4 = (x^2)^2 is always nonnegative. So (-2x+1)^4 >= 0. The coefficient -10a is either positive or negative depending on the value of 'a'. If a > 0, then -10a is negative. Making h ' (x) negative. So in this case, h(x) is monotonically decreasing always. On the flip side, if a < 0, then h ' (x) is monotonically increasing as h ' (x) is positive.

-------------------------------------------------------------

Part C. What this is saying is basically "if we change 'a' and/or 'b', then the extrema will NOT change". So is that the case? Let's find out

To find the relative extrema, aka local extrema, we plug in h ' (x) = 0
h  ' (x) = -10a(-2x+1)^4
0 = -10a(-2x+1)^4
so either
-10a = 0 or (-2x+1)^4 = 0
The first part is all we care about. Solving for 'a' gets us a = 0. 
But there's a problem. It's clearly stated that 'a' is nonzero. So in any other case, the value of 'a' doesn't lead to altering the path in terms of finding the extrema. We'll focus on solving (-2x+1)^4 = 0 for x. Also, the parameter b is nowhere to be found in h ' (x) so that's out as well. 
6 0
3 years ago
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