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Elan Coil [88]
3 years ago
8

How do you solve for x and y ??

Mathematics
1 answer:
MissTica3 years ago
5 0
See that ΔABC~ΔFGH?

that means the triangles are congruent, basically take the easy way and realize that C=H, A=F, and B=G.

y=6

now, for x, we use a²+b²=c²

so, 5²+x²=6²

(25)+x²=(36)

now we know that we need x² to equal 11

but, the square root of 11 isn't a whole number, so just put it in its radical form

x = \sqrt{11}


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a cube-shaped box has a volume of 125 cubic inches. if a box is packed full of cubes with edge lengths of 1 inch how many cubes
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Operations with Radical Expressions
lisov135 [29]

Answer: 30\sqrt{11}

<u>Step-by-step explanation:</u>

  3\sqrt{50} * \sqrt{22}

= 3\sqrt{5*5*2} * \sqrt{2*11}

= 3\sqrt{5*5*2*2*11}

= 3*5*2\sqrt{11}

= 30\sqrt{11}

******************************************

Answer: 6\sqrt{30}

<u>Step-by-step explanation:</u>

  \sqrt{20} * \sqrt{3} * \sqrt{18}

= \sqrt{2*2*5} * \sqrt{3} * \sqrt{3*3*2}

= \sqrt{2*2*5*3*3*3*2}

= 2*3\sqrt{5*3*2}

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********************************************

Answer: -\sqrt{5}

<u>Step-by-step explanation:</u>

  4\sqrt{20} - 3\sqrt{45}

= 4\sqrt{2*2*5} - 3\sqrt{3*3*5}

= 4*2\sqrt{5} - 3*3\sqrt{5}

= 8\sqrt{5} - 9\sqrt{5}

= -\sqrt{5}

********************************************

Answer: 4\sqrt{5}

<u>Step-by-step explanation:</u>

  2\sqrt{5} + 3\sqrt{5} - \sqrt{5}

= (2+3-1)\sqrt{5}

= 4\sqrt{5}

********************************************

Answer: 46\sqrt{2}

<u>Step-by-step explanation:</u>

  4\sqrt{32} + 6\sqrt{50}

= 4\sqrt{2*2*2*2*2} + 6\sqrt{2*5*5}

= 4*2*2\sqrt{2} + 6*5\sqrt{2}

= 16\sqrt{2} + 30\sqrt{2}

= 46\sqrt{2}





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4 years ago
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Answer:

B. Equilateral, and C. Acute.

Step-by-step explanation:

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3 years ago
What is the answer? X=
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Answer:

5

Step-by-step explanation:

\because \triangle ACB \cong \triangle DCE... (given) \\\therefore \angle A \cong \angle D... (c.a.c.t)\\\therefore m\angle A = m\angle D\\\therefore 50\degree = 10x\\\\\therefore x = \frac{50\degree}{10}\\\\\huge \orange {\boxed {\therefore x = 5\degree}}

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