This is what someone else answered when someone else asked it. I can't explain it better than this.
So five sibbllings ages are repressented as a,b,c,d,e let's have a as youngest and e as oldest in that order total ages are 195 so a+b+c+d+e=195 oldest is 13 older thatn youngest e=13+a middle child anne (c) is 5 years younger than josie who is an unknow position, we know that she could be d or e or oldest or second oldest the other 2 are 6 years appart b and d ar e 6 years appart or b and e are 6 years apart? or is josie the oldest, or second oldest?
second oldes is 42 so d=42
2 scenarios if josie is oldest, then see AAAA and if josie is second oldest then see BBBB
AAAA josie is 13 years older than mark e=13+a anne is 5 less than josie c=e-5 the other 2 are 6 years apart b+6=d d=42 subsitute and get b=36 add and get 78+a+c+e=195 a+c+e=117 e-13+e-5+e=117 3e-18=117 add 18 to both sides 3e=135 divided both sides by 3 e=45 subsitute a=32 b=36 c=40 d=42 e=45
BBBB oldest is 13 older than youngest e=13+a middle is 5 younger than josie (d) c=d-5 the other 2 are 6 apart b=e-6 d=42 subsitute c=37 subsitute a+b+37+42+e=195 a+b+e+79=195 subtract 79 from both sides a+b+e=116 subsitute e-13+e-6+e=116 3e-19=116 add 19 to both sides 3e=135 divide both sides by 3 e=45 subsitute 45-6=39=b 45-13=32=a c=42-5=37 this is wrong because b cannot be older than c so therefor AAA si the correct answer
THE ANSWER IS Josie is the oldest=45 Unknown is second oldest=42 Anne is middle=40 Unknown2 is second youngest=36 Mark is the youngest=32
