The rational numbers whose absolute value is 11 by 13 are

Mathematics

1 answer:

ruslelena [56]3 years ago

6 0

The rational numbers who absolute value is 11 by 13 are recurring decimal fraction.

Step-by-step explanation:

The rational numbers are included in the real numbers. On the other hand, they include the integers, natural numbers. In mathematics, a rational number is any number that can be expressed as the fraction p/q of two integers, a numerator p and a non-zero denominator q.

Absolute value means non-negative number with the same magnitude as a given number. In mathematics, the absolute value or modulus of a real number x, denoted |x|, is the non-negative value of x without regard to its sign.

Rational numbers consists of fractions which are of rational form following recurring and terminating fraction rules.

11 / 13 is a recurring fraction as it's rounded value is 0.846......

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A number increased by 9 is 13

Alborosie

Answer:

Step-by-step explanation:

To find the number you have to reverse the equation

Let us call the number "x"

x + 9 = 13

So to find x we flip the equation

13 - 9 = x

Solve it

4 = x

So the missing number is 4

6 0

3 years ago

Does the point (1, –9) satisfy the equation y = 3x − 6?

Tju [1.3M]

Answer:

No.

Step-by-step explanation:

Well, is the points (1, -9) does satisfy the equation y = 3x - 6. Then, substituting the values of x, and, y, into the equation y = 3x - 6, we should get a true equation.

y = 3x - 6

-9 = 3 * 1 - 6

-9 = 3 - 6

-9 = -3.

So, the points (1, -9) does not satisfy the equation y = 3x - 6.

8 0

3 years ago

Which of the following is not true?

cestrela7 [59]

The last statement is NOT true.

1/2 divided by 4 is 0.125 and 1/2 times 4/1 is 2

Hope I helped!

4 0

4 years ago

Read 2 more answers

Solve the system by using a matrix equation.<br> --4x - 5y = -5<br> -6x - 8y = -2

evablogger [386]

Answer:

Solution : (15, - 11)

Step-by-step explanation:

We want to solve this problem using a matrix, so it would be wise to apply Gaussian elimination. Doing so we can start by writing out the matrix of the coefficients, and the solutions ( - 5 and - 2 ) --- ( 1 )

$\begin{bmatrix}-4&-5&|&-5\\ -6&-8&|&-2\end{bmatrix}$