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3 years ago

40 80 100 how many triangles can you make

Mathematics

1 answer:

s344n2d4d5 [400]3 years ago

6 0

Answer:

infinite triangles I ready

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$12.99 Original Price and 25% discount what is the total.

mart [117]

Answer:9.75

Step-by-step explanation:

7 0

3 years ago

In the adjoining fig-5, the length and breadth of a photo

Pavel [41]

Answer:

a: 120m

b:rs. 9000

Step-by-step explanation:

Lenght:35m

Breadth:25m

Lenght of wooden strip required to frame(perimeter) = 2(L + B)

=2(35m +25m)

= 2(60m)

= 120m

Cost of wooden strip =Rs.75/m

Total cost= length of wooden strip × cost

= 120m × Rs.75/m

= Rs. 9000

5 0

3 years ago

Find the area of this shape. Show work pls. Round to the nearest hundredth.

cricket20 [7]

Answer:

35 ft²

Step-by-step explanation:

The shape is a triangle and its area is given by the formula below:

Area of triangle= ½ ×base ×height

Do note that the height has to be the perpendicular height, which is 5 ft in this case.

Area of triangle

= ½(14)(5)

= 35 ft²

8 0

3 years ago

Complete the following x^2-6x-72=(x+6)()

soldier1979 [14.2K]

Answer:

x^2-72=12x

Step-by-step explanation:

8 0

3 years ago

The Turtle and Achilles compete. They start at the same time from the same place. Achilles runs at a speed of 13 mph while the T

grandymaker [24]

Answer:

2 minutes.

Step-by-step explanation:

Let t be the time taken in competition and the distance covered by Achilles be x miles.

We have been given that when Achilles reaches the finish line, the Turtle is 2/5 of a mile behind him. This means that distance covered by turtle will be: $x-\frac{2}{5}$ .

Achilles runs at a speed of 13 mph while the Turtle moves at a speed of 1 mph.

Since we know that $\text{Time}=\frac{\text{Distance}}{\text{Speed}}$ , so we can set two equations for time taken by Achilles and turtle as:

$t=\frac{x}{13}...(1)$

$t=\frac{(x-\frac{2}{5})}{1}...(2)$

From equation (1) we will get,

$x=13t$

Upon substituting this value in equation (2) we will get,

$t=\frac{13t-\frac{2}{5}}{1}$

Let us have a common denominator.

$t=\frac{\frac{65t-2}{5}}{1}$

$t=\frac{65t-2}{5}$

Upon multiplying both sides of our equation by 5 we will get,

$5t=5\times \frac{65t-2}{5}$

$5t=65t-2$

$5t-65t=65t-65t-2$

$-60t=-2$

$t=\frac{-2}{-60}$

$t=\frac{1}{30}$

So, the competition took 1/30 hour, let us convert our given time in minutes.

$\frac{1}{30}\text{ hour}\times \frac{60\text{ minutes}}{\text{hour}}$

$\frac{1}{30}\times 60\text{ minutes}$

$2\text{ minutes}$

Therefore, the competition took 2 minutes.

8 0

3 years ago