The first thing you should do is graph the following lines
2x + 3y = 8
x-2y = -3
x = 0
y = 0
After you have graphed them, you should proceed to evaluate points in the xy plane that meet the following restrictions:
2x + 3y≤8, x-2y≥-3, x≥0, y≥0
The resulting region is the region "R" shown in the attached graph.
Choose the correct symbol for interval notation when a value is to be included in the solution
A. Parenthesis
ex
you had
x3 when x=8
it will be
(8)3
The second choice my dude
First step of a synthetic divison is that we need to carry down the leading coefficient. Here the leading coefficient is 2. So, carry down 2 at the bottom.
Next step is to multiply the divisor -3 with this carry down number 2. So, we have got 3*(-2)= -6 which will place atthe bottom of the next coefficient 4.
Next step is to add this column.
Now repeat the same method again till the last colum.
At the end we have got 0 after the addition. Which means the remainder is 0.
So, the quotient is 2x^2-2x+2.
Answer:
(2,-3)
Step-by-step explanation:
I am not sure if you meant the first equation to be y or -y. I solved it as y.
y = x-5 -x -3y =7
I am going to take the second equation and write it as x =
-x - 3y = 7 Give equation
-x = 3y +7 Add 3y to both sides
x = -3y-7 Multiplied each term in the equation by -1 so that x could be positive
I am going to substitute -3y-7 for x in the first equation up above
y = x - 5
y = -3y -7 - 5 Substitute -3y-7 for x
y = -3y -12 Combined -7-5
4y = -12 Added 3y to both sides
y = -3 Divided both sides by 4.
I now know that y is -3, I will plug that into x = -3y-7 to solve for x
x = -3(-3) -7
x = 9-7 A negative times a negative is a positive
x = 2
