Answer:
4.72 hours/day
Step-by-step explanation:
Mean time spent watching TV (μ) = 2.8 hours a day
Standard deviation (σ) = 1.5 hours a day
The 90th percentile (upper 10%) of a normal distribution has an equivalent z-score of roughly z = 1.282. The minimum time spent watching TV, X, at the 90th percentile is:
On a typical day, you must watch at least 4.72 hours of TV to be in the upper 10%.
x = y^2 + 10y + 22
Divide 10 by 2 to give 5 which becaoses the second term in the parentheses
x = (y + 5)^2 - 25 + 22
x = (y + 5)^2 - 3 Answer.
Answer:545 baseball cards
Step-by-step explanation:hope this helps!
Answer:
Step-by-step explanation:
Step 1: Write out limit
Step 2: Evaluate
(2 + 1)(3(2)² - 9)
3(3(4) - 9)
3(12 - 9)
3(3)
9