Answer:
The correct answer is B high levels of lactose and high levels of cyclic AMP.
Explanation:
Lac operon contain 3 regulatory genes and 3 structural genes.In presence of lactose the repressor molecule that is encoded by Lac I gene cannot bound to the operator region.
Bacause the lactose interact with the repressor and change its conformation so that it cannot repress the expression of the structural genes of lac operon.
On the other hand cyclic AMP is a positive regulator of lac operon .The interaction of cyclic AMP with the promoter region of lac operon stimulates the binding of RNA polymerase in the promoter region to boost the expression of structural genes of lac operon such as Lac Z,Lac Y and Lac A.
The answers are A: It will not make enough food, and C: It will not convert enough CO2 into Glucose.
Answer:
<em>The correct option is Although the F1 generation will all show the dominant trait, the offspring will all be heterozygous and increase chances of future variation.</em>
Explanation:
The cross for the offsrings that will be produced by F1 generation is shown below:
a a
A Aa Aa
A Aa Aa
As we can see that all the offsprings in the F1 generation will have heterozygous genes but only the dominant trait will be seen in the phenotype of the F1 generation.
A cross between the F1 generation will give the following results:
A a
A AA Aa
a Aa aa
This cross shows that there will be increases genetic and phenotype variations in offsprings that will be produced by the F1 plants.
Answer:
Sickle Cell Anemia:
What is the difference between sickle cell trait and sickle cell disease?
Huntington’s disease:
How does the mutant protein huntingtin cause Huntington’s disease?
Explanation:
