Given the equation
y= ![\[log_2(x)\]](https://tex.z-dn.net/?f=%20%5C%5Blog_2%28x%29%5C%5D%20)
{(1/2,?), (1, ?), (2, ?), (4,?), (8,?), (16, ?)}
Lets start with (1/2, ?)
Ordered pair is (x,y)
In (1/2, ?) , x=1/2 and we need to find out y
y= ![\[log_2(x)\]](https://tex.z-dn.net/?f=%20%5C%5Blog_2%28x%29%5C%5D%20)
Plug in 1/2 for x, y=
=
= -1
we do the same for all ordered pairs
(1, ?)
Plug in 1 for x, y=
=
= 0
(2, ?)
Plug in 2 for x, y=
=
= 1
(4, ?)
Plug in 4 for x, y=
=
= 2
(8, ?)
Plug in 8 for x, y=
=
= 3
(16, ?)
Plug in 16 for x, y=
=
= 4
Ordered pairs are
{(1/2,-1), (1, 0), (2, 1), (4,2), (8,3), (16, 4)}
Hi!
A function is when you can look at any number on the graph, and it only has one value in the line. For example, look at 2 on the y-axis. It only has one point on the line, but -2 on the y-axis has two points on the line. I hope that makes sense.
Therefore the answer is B. No, because some of the y-values are paired with 2 x-values.
Hope this helps! :)
-Peredhel
Answer:
do you need it all?
Step-by-step explanation:
Alright so I'm coming up with this on the fly; you have the first six letters (a,b,c,d,e,f) and 0-9 and your ten numbers. calculate the amount of possible combinations for the letters by simply writing them down.
ab, ac, ad, ae, a f- five
bc, bd , be, bf- four
cd, ce, cf- three
de, df- two
ef,- one.
adding these all together gets a total of 15 for the letters. now the numbers
01, 02, 03, 04, 05, 06, 07, 08, 09- nine
12, 13, 14, 15, 16, 17, 18, 19- eight
23, 24, 25, 26, 27, 28, 29- seven
34, 35, 36, 37, 38, 39- six
45, 46, 47, 48, 49- five
56, 57, 58, 59- four
67, 68, 69- three
78, 79- two
89- one
added together with a total of 45 combinations.
alright so, 45 different number combinations and 15 letter combinations. multiplying 15 by 45 should tell you the total possible combinations for a two letter and two number serial-number
Answer:
the equations is y=x+3-1
Step-by-step explanation: