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tia_tia [17]
3 years ago
11

Use the equation and type the ordered-pairs.

Mathematics
1 answer:
bulgar [2K]3 years ago
5 0

Given the equation

y= \[log_2(x)\]

{(1/2,?), (1, ?), (2, ?), (4,?), (8,?), (16, ?)}

Lets start with (1/2, ?)

Ordered pair is (x,y)

In (1/2, ?) , x=1/2 and we need to find out y

y= \[log_2(x)\]

Plug in 1/2 for x, y= \[log_2(1/2)\] = \frac{log(1/2)}{log2} = -1

we do the same for all ordered pairs

(1, ?)

Plug in 1 for x, y= \[log_2(1)\] = \frac{log(1)}{log2} = 0

(2, ?)

Plug in 2 for x, y= \[log_2(2)\] = \frac{log(2)}{log2} = 1

(4, ?)

Plug in 4 for x, y= \[log_2(1)\] = \frac{log(4)}{log2} = 2

(8, ?)

Plug in 8 for x, y= \[log_2(8)\] = \frac{log(8)}{log2} = 3

(16, ?)

Plug in 16 for x, y= \[log_2(16)\] = \frac{log(16)}{log2} = 4

Ordered pairs are

{(1/2,-1), (1, 0), (2, 1), (4,2), (8,3), (16, 4)}

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