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rewona [7]
2 years ago
8

Help asap please I need help

Mathematics
1 answer:
prisoha [69]2 years ago
6 0

Answer:

the equations is y=x+3-1

Step-by-step explanation:

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I NEED HELP ASAP!
vladimir2022 [97]

Using a geometric series, it is found that he swims 1897 yards in the first week.

In a geometric series, the quotient between consecutive terms is always the same, and it is called common ratio q.

The general equation of a geometric series is given by:

a_n = a_1q^{n-1}

In which a_1 is the first term.

The sum of the first n terms is given by:

S_{n} = \frac{a_1(1 - q^n)}{1 - q}

In this problem:

  • 200 yards on the first day, thus a_1 = 200.
  • Each day, the distance increases by 10%, since 100% + 10% = 110% = 1.1, q = 1.1.
  • First week is first 7 days, thus n = 7

Then:

S_{n} = \frac{a_1(1 - q^n)}{1 - q}

S_{7} = \frac{200(1 - 1.1^7)}{1 - 1.1}

S_{7} = 1897

He swims 1897 yards in the first week.

A similar problem is given at brainly.com/question/23711475

8 0
2 years ago
I NEED HELP PLEASE!!
Anna71 [15]

Answer:

m = 2

Step-by-step explanation:

take 2 pairs from x

choose (1,5) and (2,7)

it will be m = 5 - 7

and in the bottom  1 - 2          it's a fraction

m = -2/-1

the numerator and denominator can't be both negative

so your answer is m= +2

m= slope

rate of change= slope

7 0
2 years ago
Rewrite the formula to find w.
sveta [45]

Answer:

P / 30 - 21= 9

2w = 9

w = 4.5

This should be the answer

4 0
3 years ago
After an office party, 4 1/3 pizzas are left. A day later, there are 1 5/6 pizzas left. How munch pizza was eaten during the day
IceJOKER [234]

Answer:

15/6 pieces of pizza were eaten. Which is equivalent to 2.5. So 2.5 pizzas were eaten.

Step-by-step explanation:

Just did the math. Convert 4 1/3 to 0/6. So 1 times 2 is 2, and 3 times 2 is 6. Which would give you 4 2/6 which has the same denominator as 1 5/6.

8 0
3 years ago
Simon has a certain length of fencing to enclose a rectangular area. The function
TiliK225 [7]

Answer:

336

Step-by-step explanation:

6 0
3 years ago
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