Can a quadrilateral have 4 obtuse angles?

Mathematics

1 answer:

Viktor [21]2 years ago

7 0

NO.

The sum of their angles is 360 degrees. They can be right angles.

If one of them is obtuse then one must be of acute.

You might be interested in

How do you solve this using a picture and the work?

hoa [83]

Okkk so u need to use the Pythagorean Theorum.
$a x^{2} +b x^{2} =c x^{2}$

a=x
b=1
c=5

so...
$c x^{2} -b x^{2} =a x^{2}$

$5 x^{2} -1 x^{2} =a x^{2}$

Solve that

4 0

2 years ago

The table represents a linear equation.which equation shows how (-10,8) can be used to write the equation of this line is point-

larisa86 [58]

Answer:

$\large\boxed{y-8=-0.2(x+10)}$

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

m - slope

(x₁, y₁) - point

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

From the table we have the points (-10, 8) and (10, 4). Substitute:

$m=\dfrac{4-8}{10-(-10)}=\dfrac{-4}{20}=-\dfrac{1}{5}=-0.2$

The equation of a line:

$y-8=-0.2(x-(-10))\\\\y-8=-0.2(x+10)$

5 0

2 years ago

Read 2 more answers

Product of two natural numbers p and q is 590 and their hcf is 59. how many set of values of p and q is possible

djverab [1.8K]

$\text{Let the product of two natural numbers p and q is 590, and their HCF is 59}\\
\\
\text{we know that the product of LCM and HCF of any two numbers is equal}\\
\text{to the product of the numbers. that is}\\
\\
\text{HCF}\times \text{ LCM}=p\times q\\
\\
\Rightarrow 59 \times \text{LCM}=590\\
\\
\Rightarrow \text{LCM}=\frac{590}{59}\\
\\
\Rightarrow \text{LCM}=10\\
\\
\text{for any two natural numbers, their Least Common Multiple (LCM) is always}$