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JulijaS [17]
3 years ago
15

Can a quadrilateral have 4 obtuse angles?

Mathematics
1 answer:
Viktor [21]3 years ago
7 0

NO.

The sum of their angles is 360 degrees. They can be right angles.

If one of them is obtuse then one must be of acute.

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At a cafe, for every 5 sodas sold there are 9 teas sold. What is the ratio of teas sold to sodas sold? A) 5 : 9 B) 9 : 5 C) 9 :
frutty [35]
For 5 sodas sold, there are 9 teas sold


the ratio is tea: soda, or 9:5

B) 9:5 is your answer

hope this helps
7 0
3 years ago
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Lines e and f are parallel. The mAngle9 = 80° and mAngle5 = 55°. Parallel lines e and f are cut by transversal c and d. All angl
loris [4]

Answer:

The angle measures that are correct are m<2 = 125degrees, m<8 = 55 degrees and m<14 = 100 degrees

Given the following angles from the diagram;

m<5 = 55 degrees

m<9 = 80degrees

From the diagram

m<5 = m<1 = 55 degrees (corresponding angle)

m<1 + m<2 = 180 (sum of angle on a straight line)

Hence;

55 + m<2 = 180

m<2 = 180 - 55

m<2 = 125degrees

Also;

m<5 = m<8 = 55 degrees (vertically opposite angle)

m<9 = m<13 = 80degrees

m<13 + m<14 = 180

Hence;

80 + m<14 = 180

m<14 = 180 - 80

m<14 = 100 degrees

Hence the angle measures that are correct are m<2 = 125degrees, m<8 = 55 degrees and m<14 = 100 degrees

Step-by-step explanation:

7 0
2 years ago
Based on the graph which statement is true
Dahasolnce [82]

Answer:

D. He needs 6 cups of flour for 3 batches

6 0
3 years ago
Every blank is a rectangle
Ray Of Light [21]

Answer:

Square

Step-by-step explanation:

6 0
3 years ago
Jacob consumes an energy drink that contains caffeine. After consuming the energy drink, the amount of caffeine in Jacob's body
sasho [114]

Answer: 0.87400mg of caffeine.

Step-by-step explanation:

You have

N(t)=N0(e^−rt)(1)

as a general Exponential decay equation where N0 is the amount at t=0, N(t) is the amount remaining at time t and r is the exponential decay constant. You're specifically given that after 10 hours, the decay factor is 0.2601, i.e.,

N(10)/N(0)=N0(e^−10r)/N0(e^0)= e^−10r=0.2601 . .(2)

Taking the last 2 parts of (2) to the power of 0.1t gives

e^−rt=0.2601^.1t . .(3)

This means that

N(t)=N0(e^−rt)=N0(0.2601^.1t). .(4)

Also,

N(2.56)N(1.56)=N0(0.2601.1(2.56))N0(0.2601.1(1.56))=0.2601.1(2.56−1.56)=0.2601^.1

= 0.87400mg of caffeine.

6 0
3 years ago
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