Answer: x=4.5
not sure if it’s correct if it’s not i’m sorry
Let the slower train's velocity be x-21
Let the faster train's velocity be x
We know that the approach speed is the sum of both speeds, so x+x -21= 2x-21.
The approach rate is given by Distance/time = 471/3 = 157mpH
x+x-21=157
2x=157+21
2x=178
x=89mph
The slower train is travelling 89-21 = 68mph
The faster train is travelling 89mph.
Please find attached photograph for your answer.
Hope it helps.
Do comment if you have any query.
Answer:
in three hours he would have used up 3.75 gallons of gas. He would have 6.25 gallons of gas left in his tank after driving 3 hours.
Step-by-step e
Answer:
No solutions
Step-by-step explanation:
