You want to find
P(1000 < X < 3000)
where X is normally distributed with mean 1751 and standard deviation 421. Transform X to Z, so that it follows the standard normal distribution with mean 0 and standard deviation 1 using the relation
X = 1751 + 421Z ==> Z = (X - 1751)/421
Then
P(1000 < X < 3000) = P((1000 - 1751)/421 < (X - 1751)/421 < (3000 - 1751)/421)
… ≈ P(-1.783 < Z < 2.967)
… ≈ P(Z < 2.967) - P(Z < -1.783)
… ≈ 0.9985 - 0.0373
… ≈ 0.9612
so that approximately 96.1% of the students fall in this income range.
Answer:
a-1234 x
b-2222222f
Step-by-step explanation:
61 is the composite Number your welcome
The number is 19, 14+5=19 or 19-5=14
Answer:
6
Step-by-step explanation:
because if you get the perimeter what is 6+6+4+4 that equal to 20cm then the area would be 24 cm cubed.
