Answer:
y= -1/9(x-1)^2 +2
Step-by-step explanation:
The vertex is at (1,2) and another point is at (-2,1).
We know the vertex form of a parabola is
y= a(x-h)^2 +k where (h,k) is the vertex
Substituting the vertex in
y= a(x-1)^2 +2
We have another point, (-2,1)
Substitue this in with x=-2 and y =1. This will let us find a
1 = a(-2-1)^2 +2
1 = a (-3)^2 +2
1 = a*9 +2
Subtract 2 from each side
1-2 = 9a +2-2
-1 = 9a
Divide by 9
-1/9 = 9a/9
-1/9 =a
Putting this back into the equation
y= -1/9(x-1)^2 +2
Suppose, we are given
two points as
F as (x1, y1)
H as (x2, y2)
assume it divides in m/n
we can use formula
now, we are given points as
F=(x1, y1)=(4,8)
H=(x2, y2)=(10,12)
so,
now, we can find
so, point is
.................Answer
Answer:
12:30
Step-by-step explanation:
15+25= 40 1:10-40= 12:30
B. (3, -7)
When the equation is graphed, the vertex is at the point (3,-7). I hope this helps!!!
Answer:
there is no question for me to tell you what it is
