The conditional, <span>If four points are non-coplanar, then they are non-collinear, </span>is true:
This is, coplanarity is a necessary condition to be collinear.
The converse, <span>If four points are non-collinear, then they are non-coplanar, is false.
A counterexample that disproves this statement is the 4 vertices of a paralelogram, of course they are in a same plane and are not collinear.
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Problem # 1
3w-10=4w+5
(3w-10) + (10-4w) = (4w+5) + (10-4w)
(3w-10) + (-4w+10) = (4w+5) + (-4w +10)
3w-10-4w+10 = 4w +5 -4w +10
3w-4w=15
-w=15
w= -15 (w is negative 15)
problem #2.
6-2t > 18
6-2t-6 > 18-6
-2t > 12
(-1) (-2t) > 12 (-1)
2t > -12
next divide by 2
2t/2 > -12/2
t > -6 (t is greater then negative 6)
(Placeholder because it won’t let me ask more questions until I answer some)
