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Neko [114]
3 years ago
15

Consider the following scenario. The Current State of One Particular ArrayList The capacity of a particular ArrayList is five (5

) at some point in time. At that same time, there happens to be four (4) elements of client data in the list. The Next Operation Requested of this ArrayList From that state, a client requests to add) 25 data items to the list The Internal Reaction of the ArrayList This will certainly require an increase in the list's capacity. The question is about what actually happens internally in the time interval during which all of these twenty-five 25 add)s are executed. a. There will be no calls to ensureCapacity().b. There will be one call to ensureCapacity.c. There will be three calls to ensureCapacityd. There will be five calls to ensureCapacity).
Computers and Technology
1 answer:
pshichka [43]3 years ago
3 0

Answer:

The ArrayList initial functionality is 5, there were 4 components.

Then, add 25 more elements by using add()calling 25 times So total number of elements after the completed operation would be 4 + 25= 29.

5th component will be introduced without calling ensureCapacity(); while adding 6th element-> ensureCapacity(2* 5+ 1) it will call, making the capacity 11.

So ArrayList's capacity will be 11.

Next 7th to 11th components will also be added automatically once the 12th element is added, it will name ensureCapacity(2* 11+ 1) and make the capacity 23.

While adding 24th dimension, ensureCapacity(2* 23+ 1) will be called again and this will make the capacity 47.

There will therefore be 3 (three) calls to ensure the feature Ability).  

Elements of Rest 25th to 29th will be added seamlessly as ability becomes 47.

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a cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits such that the giv
Leokris [45]

Using the knowledge in computational language in C++ it is possible to write a code that  cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits

<h3>Writting the code:</h3>

<em>#include <bits/stdc++.h></em>

<em>using namespace std;</em>

<em>// chracter to digit mapping, and the inverse</em>

<em>// (if you want better performance: use array instead of unordered_map)</em>

<em>unordered_map<char, int> c2i;</em>

<em>unordered_map<int, char> i2c;</em>

<em>int ans = 0;</em>

<em>// limit: length of result</em>

<em>int limit = 0;</em>

<em>// digit: index of digit in a word, widx: index of a word in word list, sum: summation of all word[digit]  </em>

<em>bool helper(vector<string>& words, string& result, int digit, int widx, int sum) { </em>

<em>    if (digit == limit) {</em>

<em>        ans += (sum == 0);</em>

<em>        return sum == 0;</em>

<em>    }</em>

<em>    // if summation at digit position complete, validate it with result[digit].</em>

<em>    if (widx == words.size()) {</em>

<em>        if (c2i.count(result[digit]) == 0 && i2c.count(sum%10) == 0) {</em>

<em>            if (sum%10 == 0 && digit+1 == limit) // Avoid leading zero in result</em>

<em>                return false;</em>

<em>            c2i[result[digit]] = sum % 10;</em>

<em>            i2c[sum%10] = result[digit];</em>

<em>            bool tmp = helper(words, result, digit+1, 0, sum/10);</em>

<em>            c2i.erase(result[digit]);</em>

<em>            i2c.erase(sum%10);</em>

<em>            ans += tmp;</em>

<em>            return tmp;</em>

<em>        } else if (c2i.count(result[digit]) && c2i[result[digit]] == sum % 10){</em>

<em>            if (digit + 1 == limit && 0 == c2i[result[digit]]) {</em>

<em>                return false;</em>

<em>            }</em>

<em>            return helper(words, result, digit+1, 0, sum/10);</em>

<em>        } else {</em>

<em>            return false;</em>

<em>        }</em>

<em>    }</em>

<em>    // if word[widx] length less than digit, ignore and go to next word</em>

<em>    if (digit >= words[widx].length()) {</em>

<em>        return helper(words, result, digit, widx+1, sum);</em>

<em>    }</em>

<em>    // if word[widx][digit] already mapped to a value</em>

<em>    if (c2i.count(words[widx][digit])) {</em>

<em>        if (digit+1 == words[widx].length() && words[widx].length() > 1 && c2i[words[widx][digit]] == 0) </em>

<em>            return false;</em>

<em>        return helper(words, result, digit, widx+1, sum+c2i[words[widx][digit]]);</em>

<em>    }</em>

<em>    // if word[widx][digit] not mapped to a value yet</em>

<em>    for (int i = 0; i < 10; i++) {</em>

<em>        if (digit+1 == words[widx].length() && i == 0 && words[widx].length() > 1) continue;</em>

<em>        if (i2c.count(i)) continue;</em>

<em>        c2i[words[widx][digit]] = i;</em>

<em>        i2c[i] = words[widx][digit];</em>

<em>        bool tmp = helper(words, result, digit, widx+1, sum+i);</em>

<em>        c2i.erase(words[widx][digit]);</em>

<em>        i2c.erase(i);</em>

<em>    }</em>

<em>    return false;</em>

<em>}</em>

<em>void isSolvable(vector<string>& words, string result) {</em>

<em>    limit = result.length();</em>

<em>    for (auto &w: words) </em>

<em>        if (w.length() > limit) </em>

<em>            return;</em>

<em>    for (auto&w:words) </em>

<em>        reverse(w.begin(), w.end());</em>

<em>    reverse(result.begin(), result.end());</em>

<em>    int aa = helper(words, result, 0, 0, 0);</em>

<em>}</em>

<em />

<em>int main()</em>

<em>{</em>

<em>    ans = 0;</em>

<em>    vector<string> words={"GREEN" , "BLUE"} ;</em>

<em>    string result = "BLACK";</em>

<em>    isSolvable(words, result);</em>

<em>    cout << ans << "\n";</em>

<em>    return 0;</em>

<em>}</em>

See more about C++ code at brainly.com/question/19705654

#SPJ1

3 0
2 years ago
)In a vector implementation of a stack ADT, you add an entry to the top of a stack using which vector method?
kotykmax [81]

Answer:

B.add.

Explanation:

boolean add(element)

The add method in java inserts an element in the vector.It's return type is Boolean it returns true if the element is successfully inserted in the vector and false if the operation is unsuccessful.There is no Push operation in vector.Hence we conclude that the answer is add.

8 0
4 years ago
You are designing a VPC for a small application. It will operate in a private subnet and needs internet access to software updat
lilavasa [31]

Answer:

Refer below.

Explanation:

VPC, Subnets, Route Table(s), Nat Gateway, and Internet Gateway. These are the least required services to provide internet access to a private EC2 instance. NAT gateway requires an internet gateway.

3 0
3 years ago
Most GUIs provide all of the following except _____.
erma4kov [3.2K]

Hello there! Your answer would be A.

GUIs are Graphical user interfaces. Command prompts are unique to Windows operators, so your best option would be A since the question covers most GUIs.

Hope this helps, have a great day!

7 0
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What is one way polymorphism is implemented?
podryga [215]

Answer:

repurposing an operation

Explanation:

Got it right

8 0
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