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Rasek [7]
3 years ago
12

How is comparing 645 and 738 is different from 645 and 649

Mathematics
1 answer:
Lesechka [4]3 years ago
5 0
It's different because they have 2 different numbers<span />
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The equation of the graph line is 2X-3Y=12
Klio2033 [76]

Answer:

A. -4

Step-by-step explanation:

For solving for x intercepts analytically. You can set the the y in the equation to 0. So, 2x-3(0)=12, and solving for x will get you -4.

You can also solve graphically by plugging in the equation and looking at where it intercepts the x axis.

3 0
3 years ago
Read 2 more answers
Find the value of 2.<br> 78°<br> 1200<br> 15°<br> B
andrew11 [14]
I tried but see if this helps you In algebra, it is easy to find the third value when two values are given. Generally, the algebraic expression should be any one of the forms such as addition, subtraction, multiplication and division. To find the value of x, bring the variable to the left side and bring all the remaining values to the right side.
5 0
3 years ago
.At Phil’s work, there are 12 part-time workers and 18 full-time workers. What is the ratio of part-time workers to total worker
Scrat [10]

Answer:

  2/5

Step-by-step explanation:

The desired ratio is ...

  (part-time)/(total) = (part-time)/((part-time) +(full-time)) = 12/(12+18)

  = 12/30 = 2/5

The ratio of part-time workers to total workers is 2 : 5.

7 0
3 years ago
A rocket is fired with an initial vertical velocity of 40 m/s from a launch pad 45 m high, and its height is given by the formul
N76 [4]

Answer:

1) 125 meters

2) For 9 seconds.

Step-by-step explanation:

The rocket's height is given by the formula -5t^2+40t+45.

Notice that this is a quadratic.

Part 1)

Since this is a quadratic, the highest height the rocket goes will be the vertex of our quadratic. Remember that the vertex of a quadratic in standard form is:

(-\frac{b}{2a}, f(-\frac{b}{2a}))

So, let's identify our coefficients. The standard quadratic form is:

ax^2+bx+c

Therefore, in this case, our a is -5, b is 40, and c is 45.

So, let's find the x-coordinate of our vertex. Substitute 40 for b and -5 for a. This yields:

x=\frac{-(40)}{2(-5)}

Multiply and reduce. So:

x=-40/-10=4

Now, substitute 4 for t to find the height. So:

-5(4)^2+40(4)+45

Evaluate:

=-5(16)+40(4)+45

Multiply and add:

=-80+160+45=125\text{ meters}

Therefore, the highest the rocket goes up is 125 meters.

Part 2)

To find out for how much time the rocket is in the air, we can think about after how many seconds after launch will the rocket land.

If the rocket lands, the height h will be 0. So, we can set our expression equal to 0 and solve for t:

-5t^2+40t+45=0

First, let's divide everything by -5. This yields:

t^2-8t-9=0

We can factor:

(t+1)(t-9)=0

Zero Product Property:

t+1=0\text{ or } t-9=0

Solve for t:

t=-1\text{ or } t=9

In this case, since t is our time in seconds, -1 seconds does not make sense. So, we can remove -1 from our solution set.

Therefore, 9 seconds after launch, the rocket will touch the ground.

Therefore, the rocket was in the air for 9 seconds.

And we're done!

6 0
3 years ago
Answer....... (-1)^3×(-1)^2
8090 [49]
Hello there!

(-1)^3 * (-1)^2

Use the distributive property

= (-1)(-1)(-1)* (-1)(-1)

= (-1)^5

= -1


I hope this helps!
3 0
2 years ago
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