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12345 [234]
3 years ago
8

Cd, dvd, and blu-ray technologies can be classified as ____ storage.

Computers and Technology
1 answer:
natta225 [31]3 years ago
5 0

I guess the correct answer is magnetic

CD, DVD, and Blu-ray technologies can be classified as magnetic storage.

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You are given a class named Clock that has one int instance variable called hours.
Vlad [161]

Answer:

public Clock(int hours) {

       this.hours = hours;

   }

Explanation:

In Java programming language, Constructors are special methods that are called to initialize the variables of a class when a new object of the class is created with the new keyword. Consider the complete code for the class below;

<em>public class Clock {</em>

<em>    private int hours;</em>

<em>    public Clock(int hours) {</em>

<em>        this.hours = hours;</em>

<em>    }</em>

<em>}</em>

In this example above,  an object of this class can created with this statement Clock myclock = new Clock(6); This is a call to the constructor and passes a parameter (6) for hours

7 0
3 years ago
If your cousin wanted to view information from the world wide web, what application software would you tell her to be sure she h
MAVERICK [17]
Well, I would say a web browser, like Mozilla Firefox, Safari for IOS, Windows Edge, Chrome, or Internet Explorer; and some anti-malware software, since there are multiple websites on the WWW that try to steal your information and give your device viruses.
6 0
3 years ago
Two numbers are given (numbers are entered from the keyboard). If both numbers are positive, then output their sum, if both numb
AleksAgata [21]

Answer:

The program in Python is as follows:

num1 = int(input())

num2 = int(input())

if num1 >=0 and num2 >= 0:

   print(num1+num2)

elif num1 <0 and num2 < 0:

   print(num1*num2)

else:

   if num1>=0:

       print(num1**2)

   else:

       print(num2**2)

Explanation:

This gets input for both numbers

num1 = int(input())

num2 = int(input())

If both are positive, the sum is calculated and printed

<em>if num1 >=0 and num2 >= 0:</em>

<em>    print(num1+num2)</em>

If both are negative, the products is calculated and printed

<em>elif num1 <0 and num2 < 0:</em>

<em>    print(num1*num2)</em>

If only one of them is positive

else:

Calculate and print the square of num1 if positive

<em>    if num1>=0:</em>

<em>        print(num1**2)</em>

Calculate and print the square of num2 if positive

<em>    else:</em>

<em>        print(num2**2)</em>

3 0
2 years ago
#Imagine you're writing a program to check if a person is
irakobra [83]

Answer:

i hope the program below will help you!

Explanation:

5 0
3 years ago
an IPv6 packet has a 40 byte base header, a 20 byte destination options extension header (which is not used for routing) and 200
NISA [10]

Answer:

Explanation:

Given, total payload is: 2000 bytes

 MTU is: 1500 bytes

 Header is: 20 bytes

 Base header is: 40 bytes

Total number of fragments = Total Payload / MTU

                                            = 2500 / 1500

                                            = 2 fragments

Fragment     Base header    Fragmentation header     Authentication  

                                                                                                     header + Data

1                  40 bytes                  8 bytes                              20 bytes +772bytes

2                 40 bytes                   8 bytes                                 792 bytes

7 0
3 years ago
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