X^2+(y+1)^2=4^2 a formula general
ES URGENTEEEEEE
grax<3
1 answer:
Answer:
circle centered at (0,-1) and radius 4.
Step-by-step explanation:
The equation of a circle of radius r, with center is (a,b) is
(x-a)^2+(y-b)^2=r^2.
x^2+(y+1)^2=4^2=(x-0)^2+(y-(-1))^2=4^2 so that a=0, b--1 and r=4.
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