Ask question

Ask question

All categories

3 years ago

13

Billy has 1 gallon of paint. He is going to pour it into a paint tray that measures 10 inches wide, 14 inches long, and 4 cm dee

p.
(1 gallon = 231 in3, 1 inch = 2.54 cm)
hich of the following scenarios will happen?

The paint will not fill the tray by 441 cm3.
The paint will not fill the tray by 10.53 in3.
The paint will fill the tray exactly.
The paint will overfill the tray by 10.53 in3.

2 answers:

Leona [35]3 years ago

7 0

Answer:

The answer is:

The paint will overfill the tray by 10.53 in3 (cubic inches).

Step-by-step explanation:

In order to determine the correct option, first we have to get the volume of the tray.

The volume of the tray is a solid prism, where its formula is:

width=10 in

length=14 in

deep=4 cm= $\frac{4}{2.54} =1.575$ in

Volume= $10*14*1.57=220.5$ cubic inches

The value of the deep measure was changed from cm to inches units.

We subtract the allowed volume of the gallon with the volume tray:

231-220.5=10.5 cubic inches

It means that 1 gallon of paint is enough to paint the tray, where the remaining paint is 10.5 cubic inches.

Finally, the correct option is:

The paint will overfill the tray by 10.53 in3 (cubic inches).

Blababa [14]3 years ago

5 0

find volume of tray:

convert 4cm to inches 4/2.54 = 1.575 inches

volume = 10*14*1.575 = 220.47 cubic inches

1 gallon = 231 cubic inches

231-220.47 = 10.53 more paint in a gallon

so the paint will over fill the tray by 10.53 in3

You might be interested in

On a trip, Duke encounters some road construction that slows him down. While he is able to go 60 mph on the highway and 40 mph t

natulia [17]

Answer:

Time taken by Duke on the highway = 3 hours

Time spent on the construction = 6 hours

Time spent in the city = 2 hours

Step-by-step explanation:

Speed by which Duke travels a distance on highway $d_1$ = 60 mph

Let the time taken to travel on highway = $t_1$ hours

Distance traveled = $60t_1$ miles

Speed in the city = 40 mph

Let the time taken = $t_2$ hours

Distance traveled in the city = $40t_2$ miles

Speed on the construction = 20 mph

Let the time spend on the construction = $t_3$ hours

Distance traveled on the construction = $20t_3$ miles

Since, total distance covered = 380 miles

$d_1+d_2+d_3=60t_1+40t_2+20t_3$

He spends one half the time on the highway as he does on the construction,

$t_3=2t_1$

Total time spent in the trip = 11 hours

Therefore, $t_1+t_2+t_3=11$

$t_1+t_2+2t_1=11$

$t_2=11-3t_1$

From equation (1),

$60t_1+40(11-3t_1)+20(2t_1)=380$

$60t_1-120t_1+40t_1+440=380$

$440-20t_1=380$

$20t_1=440-380$

$t_1=\frac{60}{20}$

$t_1=3$ hours

$t_2=11-3t_1=2$ hours

$t_3=2t_1=6$ hours

Therefore, time taken by Duke on the highway = 3 hours

Time spent on the construction = 6 hours

Time spent in the city = 2 hours

3 0

3 years ago

Help Asap 20 points!! And Brainlist!!!

Alenkasestr [34]

Answer: 2(5c - 1x)

Step-by-step explanation: It's asking you to take out the greatest common factor (GCF).

5 0

3 years ago

Tiffany wants to illustrate the homework times she and some of her friends spent one night on one subject. Her goal is to show t

chubhunter [2.5K]

My best guess is a line graph because it shows the consistent numbers and then you can lay them all out after you have completed the graph

8 0

3 years ago

Read 2 more answers

According to the Centers for Disease Control, about 18% of adolescents age 12-19 are obese. Suppose we take a random sample of 3

ivann1987 [24]

Answer:

the sampling distribution of proportions

Step-by-step explanation:

A sample is a small group of observations which is a subset of a larger population containing the entire set of observations. The proportion of success or measure of a certain statistic from the sample, (in the scenario above, the proportion of obese observations on our sample) gives us the sample proportion. Repeated measurement of the sample proportion of this sample whose size is large enough (usually greater Than 30) in other to obtain a range of different proportions for the sample is called the sampling distribution of proportion. Hence, creating a visual plot such as a dot plot of these repeated measurement of the proportion of obese observations gives the sampling distribution of proportions

6 0

3 years ago

How many liters of 60% alcohol solution should be added to 40 liters of a 20% alcohol solution to make a 50% solution?

kolbaska11 [484]

Answer:

120 liters of 60% alcohol solution is needed

Step-by-step explanation:

Let's assume

x liters of 60% alcohol solution is added

so, we get solution as

$=\frac{60}{100}\times x$

$=0.6x$

we are given

40 liters of a 20% alcohol solution is

$=40\times\frac{20}{100}$

$=40\times\frac{20}{100}$

$=8$

so, total alcohol solution is

$=8+0.6x$

now, we can find total solutions

total solutions is

$=x+40$

now, it is making 50% solution

so, we get

$\frac{8+0.6x}{x+40} =\frac{50}{100}$

now, we can solve for x

$\left(8+0.6x\right)\cdot \:100=\left(x+40\right)\cdot \:50$

$800+60x=50x+2000$

$10x=1200$

$x=120$

So,

120 liters of 60% alcohol solution is needed

4 0

3 years ago