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zhannawk [14.2K]
3 years ago
8

Ricky can ride 17 km on his bike in the same length of time ha can walk 9 km.if his riding speed is 4 kph faster than his walkin

g speed how fast does he walk
Mathematics
1 answer:
aivan3 [116]3 years ago
5 0
Distance=speed times time
if they take the same time, we cal the time , t

b=bike speed
w=walking speed

bikedistnace=17=bt
walkdistance=9=wt

b is 4 more than w
b=4+w

we have
17=bt
9=wt
b=4w

ok so
multiply first equation by 9 and 2nd by 17

153=9bt
153=17wt
set equal
9bt=17wt
divide both sides by t
9b=17w
sub b=4+w for b
9(4+w)=17w
distribute
36+9w=17w
minus 9w both sides
36=8w
divide both sides by 8
4.5=w

he walks 4.5kph
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Step-by-step explanation:

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<h3>Answer:   7 goes in the blank space</h3>

The range of values for x is 2 < x < 7

========================================

Explanation:

The hinge theorem says that the larger the opposite side is, the larger the angle will be.

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Since AD > DC, this means angle ABD > angle DBC.

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4x < 28 ... flip both sides and the inequality sign

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--------

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