A: 55
b: 50
c: 100
the sum of all the angles of a triangle must equal 180
Got it. Hope this will help.
Answer:
<u>Solution</u><u> </u><u>given</u><u>:</u>
<u>one</u><u> </u><u>side</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>triangle</u><u> </u><u>must</u><u> </u><u>be</u><u> </u><u>less</u><u> </u><u>than</u><u> </u><u>the</u><u> </u><u>sum</u><u> </u><u>of</u><u> </u><u>two</u><u> </u><u>other</u><u> </u><u>side</u><u> </u><u>.</u>
<u>by</u><u> </u><u>making</u><u> </u><u>these</u><u> </u><u>sense</u><u>:</u>
3<10+20
10<20+3
20<10+3not true
these three side are not possible.
again
10<20+25
20<25+10
25<20+10
these three side are true so
required side are:
Side 1:10
Side 2:25
Side 3:20
The answer would be 13 1/2 because you turn the 12 into a fraction then change the division sign into a multiplication sign and find the reciprocal of 8/9 which is 9/8 you could now divide 12/1 divided by 9/8 you could cross simply then dove to get 27/2 and in the end you get 13 1/2 if you turn the improper fraction into a mixed number.
