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Tems11 [23]
3 years ago
5

ou own a classic car that is currently valued at $64,000. If the value increases by 2.5 percent annually, how much will the car

be worth 15 years from now
Business
1 answer:
Fynjy0 [20]3 years ago
7 0

Answer:

$92,691.08

Explanation:

The computation of the future value is shown below:

As we know that

Future value = Present value × (1 + interest rate)^number of years

where,

Present value is $64,000

The Interest rate is 2.5%

And, the number of the year is 15 years

Now placing these values to the above formula

So, the future value is

= $64,000 × (1 + 0.025)^25

= $64000 × 1.448298166

= $92,691.08

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To what degree, if at all, is a significant deficiency related to a material weakness? It is less severe than a material weaknes
Brut [27]

Answer: It is less severe than a material weakness

Explanation:

A SIGNIFICANT DEFICIENCY is described as a deficiency or an amalgamation of deficiencies that are NOT as severe as a MATERIAL WEAKNESS ( which is quite serious and must be reported to the Audit Committee and be reflected in the financial statements) but still important enough for those people in charge of the company's financial records to take notice.

5 0
3 years ago
Identify whether each of the following statements best illustrates the concept of consumer surplus, producer surplus, or neither
sertanlavr [38]

Answer: Statement 1 ( Laptop) = Producer surplus

              Statement 2 ( watch ) = Neither

              Statement 3 ( jersey sweater) = Consumer surplus

Explanation:

Hi, Consumer surplus happens when the price that consumers pay for a product or service is less than the price they're willing to pay.

  • <em>Even though I was willing to pay up to $46 for a jersey sweater, I bought a jersey sweater for only $39.  </em>Consumer surplus

Producer surplus<em>  </em> is measured as the difference between what producers are willing and able to supply a good for and the price they actually receive

  • <em> I sold a used laptop for $149, even though I was willing to go as low as $140 .</em>Producer surplus
  • <em>I sold a watch for $59 on eBay last week. This week, someone offered me $145 for it.  </em>neither

Feel free to ask for more if needed or if you did not understand something.

5 0
3 years ago
The number of shares of a class of stock that are outstanding is: Multiple Choice the number of shares authorized minus the numb
RoseWind [281]

Answer:

The number of shares of a class of stock that are outstanding is:

the number of shares issued minus the number of shares held as treasury stock.

Explanation:

A company's outstanding shares include the total shares issued minus the treasury stock shares.  Treasury stock shares are shares that the company has repurchased from their former stockholders.  They can be held for resale, to pay for stock options to employees, or they are retired completely.  The number of outstanding shares is an ingredient used in computing the earnings per share (EPS), an important financial metric for investors.

5 0
3 years ago
True or False: Used items like used clothing, electronics, and furniture are included in the computation for GDP because buyers
aliina [53]

Answer:

False

Used item clothings aren't included in GDP.

The GDP includes only items produced in a given year. The items would have been included in the year they were produced and adding them to GDP again would be double counting

Explanation:

Gross domestic product is the sum of final goods and services produced in an economy within a given period which is usually a year.

GDP calculated using the expenditure approach = Consumption spending + Investment spending by businesses + Government Spending + Net Export

I hope my answer helps you

4 0
3 years ago
Let S represent the amount of steel produced (in tons). Steel production is related to the amount of labor used (L) and the amou
Phantasy [73]

Solution

S = 15 x L^{0.2} x C^{0.8}

Total cost, T = wL + rC = 50L + 100C

Total revenue, R = Output price (P) x Quantity = P x 15 x L^{0.2}x C^{0.8}

(a)

Optimization problem will be:

Max R = P x 15 x L^{0.2} x C^{0.8}

Subject to T = 50L + 100C

(b) When S = 50,000

Cost is minimized when (MPL / MPC) = w / r

MPL = \partialR / \partialL = P x 15 x 0.2 x (C / L)^{0.8} = P x 3 x (C / L)^{0.8}

MPC = \partialR / \partialC = P x 15 x 0.8 x (L / C)^{0.2} = P x 12 x (L / C)^{0.2}

MPL / MPC = (3/12) x (C / L) = 50/100

C / 4L = 1/2

4L = 2C

2L = C

Substituting in production function,

15 x L^{0.2} x C^{0.8} = S

15 xL^{0.2} x (2L)^{0.8} = 50,000

15 x 2^{0.8} x L^{0.2} x L^{0.8} = 50,000

L = 50,000 / (15 x 20.8)

L = 1,914.50

C = 2L = 3,829.00

Total cost ($) = 50 x 1,914.50 + 100 x 3,829.00 = 95,725.00 + 382,900 = 478,625.00

Note: This optimization problem can be solved without using Solver too, as shown here.

6 0
3 years ago
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