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solong [7]
3 years ago
8

Which of the following factors influences the speed of a wave? I. the type of wave II. the amplitude of the wave III. the medium

in which the wave travels
Physics
2 answers:
Nata [24]3 years ago
3 0

I. the type of wave ... electromagnetic or mechanical

(II. amplitude doesn't influence the speed of any wave)

III. the medium in which the wave travels ... completely determines the wave speed

S_A_V [24]3 years ago
3 0

Answer: The correct answers are (I) and (III).

Explanation:

The expression for the relation between the speed of the wave and the frequency is as follows;

v=f\lambda

Here, f is the frequency and \lambda is the wavelength.

The speed of the wave depends on the medium in which the wave travels.

It depends on the type of wave but it does not depend on the amplitude of the wave.

For example, the speed of the sound wave is more in the solid medium in comparison to the liquid and gaseous medium as the solid medium is more dense. Here, the particles are more closer.

The speed of light is more than the speed of the sound. Light is transverse wave whereas sound wave is longitudinal wave.

Therefore, the factors which influence the speed of a wave are as follows;

the type of wave (II )and (III) the medium in which the wave travels.

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A diffraction grating is illuminated simultaneously with red light of wavelength 660 {\rm nm} and light of an unknown wavelength
Tanzania [10]

Answer:

\lambda = 420 nm

Explanation:

As we know that position of maximum on the screen in diffraction pattern is given as

y = (\frac{2N + 1}{2})\frac{\lambda L}{d}

here we know that

position of third maximum due to red color light and position of fifth maximum of unknown wavelength are same

so we have

\frac{7 \lambda_r L}{2d} = \frac{11 \lambda L}{2d}

so we have

\lambda = \frac{7}{11} \lambda_r

\lambda = \frac{7}{11}(660 nm)

\lambda = 420 nm

7 0
4 years ago
Which statement is true about light when it slows down upon entering another medium
yarga [219]
The answer should be B

5 0
4 years ago
Read 2 more answers
Joanna drove a car at 30km/hr. What is the speed in m/s?
Aloiza [94]
8.33 m/s
Explain:

If you understand what 1 km = 1000 m and 1 hr = 60*60 seconds signify, you already know what they mean. If you translate 1000 m/ 3600 s to km/hr, you'll get 5 m/ 18 s, which you can multiply by 30 to get (30 x 5)/18 = 8.33 m/s.
7 0
3 years ago
How much work in joules must be done to stop a 920-kg car traveling at 90 km/h?
tankabanditka [31]

Answer:

Work done, W = −287500 Joules

Explanation:

It is given that,

Mass of the car, m = 920 kg

The car is travelling at a speed of, u = 90 km/h = 25 m/s

We need to find the amount of work must be done to stop this car. The final velocity of the car, v = 0

Work done is also defined as the change in kinetic energy of an object i.e.

W=\Delta K

W=\dfrac{1}{2}m(v^2-u^2)

W=\dfrac{1}{2}\times 920\ kg(0-(25\ m/s)^2)

W = −287500 Joules

Negative sign shows the work done is done is opposite direction.

3 0
3 years ago
You are pulling a sled using a horizontal rèpe, as shown in the diagram. The rope pulls the sled. exerting a force of 50 N to th
Luden [163]

Answer:

Explanation:

From your other post, the complete question is:

"You are pulling a sled using a horizontal rèpe, as shown in the diagram. The rope pulls the sled. exerting a force of 50 N to the right. The snow exerts a friction force of 30 N on the sled to the left. The mass of the sled is 50 kg.

Find the sum of the force on the sled.

Determine the acceleration of the sled .

If the sled has an initial velocity 2m/s to the right, how fast will it be traveling after 5 seconds?

"

Given the rope exerting a force of 50 N to the right and the snow exerts a friction force of 30 N to the left, the sum of forces

= 50 - 30

= 20N to the right

The mass of sled is 50 kg and force = mass * acceleration.

Acceleration = Force / mass

= 20 / 50 = 0.4 m/s^2 to the right

If the sled has an initial velocity 2m/s to the right, after 5 seconds it will be traveling at initial velocity + acceleration * time

= 2 + 0.4*5

= 4 m/s to the right

3 0
3 years ago
Read 2 more answers
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