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tatiyna
3 years ago
15

A 2578-kg van runs into the back of a 825-kg compact car at rest. They move off together at 8.5 m/s. Assuming the friction with

the road is negligible, calculate the initial speed of the van.
Physics
1 answer:
allochka39001 [22]3 years ago
3 0

Answer:

<em>The initial speed of the car = 11.22 m/s</em>

Explanation:

Law of conservation of energy: It states that when two bodied collide in a closed system, the sum of momentum before collision is equal to the sum of momentum after collision.

<em>Note:</em> A close system is one that is free from from external forces. E.g Frictional force.

From the law of conservation of momentum,

Total momentum before collision = Total momentum after collision.

m₁u₁ + m₂u₂ = (m₁ + m₂)V..................... Equation 1

Where m₁ = mass of the van, m₂ = mass of the car, u₁ = initial velocity of the van, u₂ = initial velocity of the car, V = Common velocity.

<em>Given: m₁ = 2578 kg, m₂ = 825 kg, u₂ = 0 ( the car was at rest), V= 8.5 m/s</em>

<em>Substituting these values into equation 1, and solving for u₁</em>

<em>2578(u₁) + (825 × 0) = (2578 + 825)8.5</em>

<em>2578u₁ = 28925.5</em>

<em>Dividing both side of the equation by the coefficient of u₁</em>

<em>2578u₁/2578 = 28925.5/2578</em>

<em>u₁ = 11.22 m/s</em>

<em>The initial speed of the car = 11.22 m/s</em>

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