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julsineya [31]
3 years ago
10

What is the interquartile range of the data set {23,30,24,28,27,24,26}?

Mathematics
1 answer:
IrinaK [193]3 years ago
3 0

Answer:

IQR=4

Step-by-step explanation:

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What is the quotient of 5 divided by 1/3
Pachacha [2.7K]

Answer:

15

Step-by-step explanation:

5 divided by 1/3 is the same as if you flip the denominator meaning 5 x 3 which is 15

4 0
3 years ago
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You can park no further than how many feet away from the curb
ivolga24 [154]
The answer is 18 inches.
6 0
3 years ago
Why is the number of operators per shift multiplied by approximately 4.5 to obtain the total number of operators required to run
4vir4ik [10]

I believe you meant "why is the number of shifts multiplied by approximately 4.5 to obtain the total number of operators required to run the plant"

Answer and Explanation:

There are 3 shifts per day, 49 weeks per year and 5 shifts per operator per week

To get total number of operators required to run the plant, we multiply number of shifts in a year by number if operators per shift.

49 weeks×5 shifts= 245 shifts per operator per year

365×3 shifts= 1095 shifts per year

1095/245=4.5 operators per shift

total number of operators required to run the plant(per day) = 4.5×3= 13.5 approximately 14

total number of operators required to run the plant(per year) =4.5×1095=4927.5 approximately 4928

3 0
3 years ago
Which of the following
Ronch [10]

Answer:

Option A

Step-by-step explanation:

<u>Given equation is</u>

=> 3y = 6x + 3

<u>In slope-intercept form, it becomes</u>

=> 3y = 3(2x+1)

=> y = 2x+1

So, Slope = m = 2

<u><em>Parallel lines have equal slope, So any line parallel to the above line would have its slope equal to 2</em></u>

=> Line parallel to 3y = 6x + 3 is y = 2x + 10

3 0
3 years ago
Solve 12^x^2+5x-4 = 12^2x+6
faust18 [17]

The solutions for ‘x’ are 2 and -5

<u>Step-by-step explanation:</u>

Given equation:

                    12^{x^{2}+5 x-4}=12^{2 x+6}

Since the base on both sides as ‘12’ are the same, we can write it as

                     x^{2}+5 x-4=2 x+6

                     x^{2}+5 x-2 x-4-6=0

                     x^{2}+3 x-10=0

Often, the value of x is easiest to solve by a x^{2}+b x+c=0 by factoring a square factor, setting each factor to zero, and then isolating each factor. Whereas sometimes the equation is too awkward or doesn't matter at all, or you just don't feel like factoring.

<u>The Quadratic Formula:</u> For a x^{2}+b x+c=0, the values of x which are the solutions of the equation are given by:

                       x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Where, a = 1, b = 3 and c = -10

                       x=\frac{-3 \pm \sqrt{(-3)^{2}-4(1)(-10)}}{2(1)}

                       x=\frac{-3 \pm \sqrt{9+40}}{2}

                       x=\frac{-3 \pm \sqrt{49}}{2}=\frac{-3 \pm 7}{2}

So, the solutions for ‘x’ are

                       x=\frac{-3+7}{2}=\frac{4}{2}=2

                       x=\frac{-3-7}{2}=\frac{-10}{2}=-5

The solutions for ‘x’ are 2 and -5

6 0
2 years ago
Read 2 more answers
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