All categories

3 years ago

Can someone explain INTERQUARTILE RANGE for me, and please give an example. Thank you!

2 answers:

7 0

Https://www.khanacademy.org/math/cc-sixth-grade-math/cc-6th-data-statistics/cc-6th/v/calculating-interquartile-range-iqr This is a link that I gave to my little sister that helped her understand what interquartile range is. It has an example as well! I hope this helps!

AURORKA [14]3 years ago

3 0

Https://www.khanacademy.org/math/cc-sixth-grade-math/cc-6th-data-statistics/cc-6th/v/calculating-interquartile-range-iqr Link video explains everything with examples it helped me hope it helpes you

You might be interested in

A car dealership had $114,000 in average monthly sales. If you made 30% of all the sales, what is your total sales? help me

Tcecarenko [31]

Answer:

I think it's $34,200

Step-by-step explanation:

$114,000 x 30% divide 100 = 34,200

6 0

3 years ago

WHO WANTS BRAINLIEST THEN ANSWER THIS QUESTION

elena-14-01-66 [18.8K]

Answer:

Step-by-step explanation:

cyril was completing a uniform velocity at first and then had a slight decrease in its speed..and then again..increased its velocity all through the journey...

gertie had a uniform speed till 17 cm/s and the had a decrease in its velocity ... and finally got back to its initial velocity...

harold was increasing its velocity from rest and then took rest after 15 metres and then again moved with an increasing velocity after 40 seconds

7 0

3 years ago

If a finite set S of nonzero vectors spans a vector space V , then some subset of S is a basis for V . True or False

andreyandreev [35.5K]

<h3>Answer: True</h3>

Explanation:

This theorem doesn't have a name unfortunately. So searching it out is a bit tricky if you don't know the right way to word things. Luckily it wasn't too hard of a find, and I managed to track it down in a linear algebra textbook.

Check out the screenshot below for the snippet of the theorem and the corresponding proof. The book simply refers to it as "theorem 1.9", which again, is an unfortunate choice of naming.

3 0

3 years ago

Need help please and thank you

mojhsa [17]

Answer:

Step-by-step explanation:

A = 4pier²

A/4pie = r²

Under root (A/4pie) = r

Hope it helps.

3 0

3 years ago

Q 2 PLEASE HELP ME FIGURE THIS OUT

suter [353]

Answer: IV, positive, $\frac{\pi} {6}$ , - sec $\frac{\pi} {6}$ , $\frac{2\sqrt{3}}{3}$

Step-by-step explanation:

a) Look at the Unit Circle to see that $\frac{11\pi} {6}$ = 330°, which is located in Quadrant IV.

b) The coordinate (cos θ, sin θ) for $\frac{11\pi} {6}$ is: $(\frac{\sqrt{3}} {2},\frac{-1}{2})$

sec = $\frac{1}{cos}$ = $\frac{2}{\sqrt{3}}$ which is positive

c) Since the given angle is in Quadrant IV, which is closest to the x-axis at 360° = 2π, the reference angle can be found by subtracting the given angle $\frac{11\pi} {6}$ from 2π: $\frac{12\pi} {6}$ - $\frac{11\pi} {6}$ = $\frac{\pi} {6}$

d) the reference angle is below the x-axis so the given angle is equal to the negative of the reference angle: - sec $\frac{\pi} {6}$ .

e) sec $\frac{11\pi} {6}$ = $\frac{2}{\sqrt{3}}$ = $\frac{2}{\sqrt{3}}*\frac{\sqrt{3}}{\sqrt{3}}$ = $\frac{2\sqrt{3}}{3}$

***************************************************************************************

Answer: $\frac{18\pi}{11}$ , IV, $\frac{4\pi} {11}$

Step-by-step explanation:

2π is one rotation. 2π = $\frac{22\pi}{11}$

$\frac{-26\pi}{11}$ + $\frac{22\pi}{11}$ = $\frac{-4\pi}{11}$

$\frac{-4\pi}{11}$ + $\frac{22\pi}{11}$ = $\frac{18\pi}{11}$

Convert the radians into degrees to see which Quadrant it is in by setting up the proportion and cross multiplying:

$\frac{\pi}{180}$ = $\frac{18\pi}{11x}$

π(11x) = (180)18π

x = $\frac{180(18\pi}{11\pi}$

x = 295° which lies in Quadrant IV

Since the given angle is in Quadrant IV, which is closest to the x-axis at 360° = 2π, the reference angle can be found by subtracting the angle of least nonegative value $\frac{18\pi} {11}$ from 2π: $\frac{22\pi} {11}$ - $\frac{18\pi} {11}$ = $\frac{4\pi} {11}$

***************************************************************************************

Answer: $\frac{5\pi}{3}$ , IV, $\frac{4\pi} {11}$ , $\frac{\pi} {3}$

Step-by-step explanation:

2π is one rotation. 2π = $\frac{6\pi}{3}$

$\frac{-13\pi}{3}$ + $\frac{6\pi}{3}$ = $\frac{-7\pi}{3}$

$\frac{-7\pi}{3}$ + $\frac{6\pi}{3}$ = $\frac{-\pi}{3}$

$\frac{-\pi}{3}$ + $\frac{6\pi}{3}$ = $\frac{5\pi}{3}$

This is on the Unit Circle at 300°, which is located in Quadrant IV

Since the given angle is in Quadrant IV, which is closest to the x-axis at 360° = 2π, the reference angle can be found by subtracting the angle of least nonegative value $\frac{5\pi} {3}$ from 2π: $\frac{6\pi} {3}$ - $\frac{5\pi} {3}$ = $\frac{\pi} {3}$

7 0

4 years ago