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Nady [450]
3 years ago
11

I need help finding missing angle​

Mathematics
1 answer:
LiRa [457]3 years ago
4 0

Answer:

The picture

Step-by-step explanation:

Use the supplementary theorem and corresponding theorem. :)

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Convert the polar equation to rectangular form: <br><br> r = 2 / [1 + sin(theta)]
iren2701 [21]
R = 2 / (1 + sin <span>θ)

Using the following relations:

R = sqrt (x^2 + y^2)
sin </span>θ = y/R
<span>
R = 2 / (1 + y/R)
R</span>(1 + y/R<span>) = 2
</span><span>R + y = 2
R = 2 - y
sqrt(x^2 + y^2) = 2 - y

Squaring both sides:
x^2 + y^2 = (2 - y)^2
x^2 + y^2 = 4 - 4y + y^2

x^2 + 4y - 4 


</span>
8 0
3 years ago
In the 1920s, the continued rise in the stock market and economic growth depended most on
Pachacha [2.7K]
Credit. That's why the stock market crash was so terrible in 1929. 
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3 years ago
Petrolyn motor oil is a combination of natural oil and synthetic oil. It contains 7 liters of natural oil for every 5 liters of
Svetach [21]
What we know:
Petrolyn motor oil is a combination of natural oil and synthetic oil. It contains 7 liters of natural oil for every 5 liters of synthetic oil.

What we need to find:
If 355 liters of synthetic oil are used, how many liters of petrolyn oil will be made?

Set up a proportion to find how much natural oil is used.
7L natural oil/5L synthetic oil = x/355 synthetic oil where x=natural oil
7/5=x/355
(5)(x)=(7)(355) cross multiplied
5x=2485 simplified
5/5x=2485/5 multiplicative inverse
x=497L

Now, add both synthetic oil and natural oil to find amount of petrolyn oil.

355 L synthetic oil + 497 L natural oil= 852 L of petrolyn oil
5 0
3 years ago
Can someone please help me answer these 6 questions?
Mamont248 [21]
1) 19.25

2) 12.92

3) 25.20

4) 19.68

5) 77.05

6)81.67
8 0
3 years ago
A circle with radius of 4 cm sits inside a circle with radius of 11 cm.
kap26 [50]

The area of the shaded region = 330 sq cm

Step-by-step explanation:

Given,

The radius of small circle (r) = 4 cm

The radius of large circle (R) = 11 cm

To find the shaded region

Formula

The area of circle of radius r = πr^{2} sq cm

So, The radius of the small circle = π×4^{2} sq cm = 16π sq cm

The radius of the large circle = π×11^{2} sq cm = 121π sq cm

Hence the area of the shaded region = 121π-16π sq cm

= 105π sq cm

= 105 × \frac{22}{7} sq cm = 330 sq cm

5 0
3 years ago
Read 2 more answers
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