You mix 6 quarts of sprite with 2 gallons of orange sherbet. How many quarts of sprite will be needed for 4 gallons of sherbet?

PLEASE HELP DUE IN 10 MINS OMG PLS HELP RN

skad [1K]

Answer:

D

Step-by-step explanation:

3 0

3 years ago

Explain your answer !! <br> Have a nice day

gregori [183]

Oh gosh oh I don’t have to get My to come

7 0

3 years ago

. Lightning Strikes It has been said that the probability of being struck by lightning is about 1 in 750,000, but under what cir

mrs_skeptik [129]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

$P(U |D ) = 0.198$

b

$P(O\ n \ B) = 0.188$

c

$P(O | B) = 0.498$

Step-by-step explanation:

The total number of deaths is mathematically represented as

$T = 16 + 23 + \cdots + 16$

$T =623$

The total number of deaths in 1996 - 2000 is mathematically represented as

$T_a = 16 + 23+ \cdots + 30$

$T_a = 235$

The total number of deaths in 2001 - 2005 is mathematically represented as

$T_b = 17 + 16 + \cdots + 23$

$T_b = 206$

The total number of deaths in 2006 - 2010 is mathematically represented as

$T_c = 15 + 17 + \cdots + 16$

$T_d = 182$

Generally the the probability that it would occur under the tree given that the death was after 2000 is mathematically represented as

$P(U |D ) = \frac{P(A \ n\ U )}{P(A)}$

Here $P(A \ n\ U )$ represents the probability that it was after 2000 and it was under the tree and this is mathematically represented as

$P(A \ n\ U ) = \frac{Z}{ T}$

Here Z is the total number of death under the tree after 2000 and it is mathematically represented as

$Z = 35 + 42$

=> $Z = 77$

=> $P(A \ n\ U ) = \frac{77}{ 623}$

=>

Also

$P(A)$ is the probability of the death occurring after 2000 and this is mathematically represented as

$P(A) = \frac{T_b + T_c}{ T}$

=> $P(A) = \frac{ 206+ 182}{623}$

=>

So

$P(U |D ) = \frac{\frac{77}{ 623} }{ \frac{ 206+ 182}{623}}$

=> $P(U |D ) = 0.198$

Generally the probability that the death was from camping or being outside and was before 2001 is mathematically represented as

$P(O | B) = \frac{T_z}{ T}$

Here $T_z$ is the total number of death outside / camping before 2001 and the value is 117

So

$P(O \ n \ B) = \frac{117}{623}$

=> $P(O\ n \ B) = 0.188$

Generally the probability that the death was from camping or being outside given that it was before 2001 is mathematically represented as

$P(O | B) = \frac{ P( O \ n \ B)}{ P(B)}$

Here $P(B)$ is the probability that it was before 2001 , this is mathematically represented as

$P(B ) = \frac{T_a}{T}$

=> $P(B ) = \frac{235}{623}$

So

$P(O | B) = \frac{ \frac{117}{623}}{ \frac{235}{623}}$

=> $P(O | B) = 0.498$

5 0

3 years ago

Need help please!!!

forsale [732]

The answer is D
Explanation:5x^5-44x^3-9x=0
X(5x^2+1)(x-3)(x+3)=0
X(x+3)(x-3)=0
X=0,x=-3,x=3

3 0

3 years ago

Read 2 more answers

A contractor is building a fenced-in area at a daycare. The area will be rectangular with the length of its base equal to half t

AlladinOne [14]

Answer:

The length of fencing will be $300\ ft$

Step-by-step explanation:

Step 1

Find the dimensions of the rectangle

we know that

The area of a rectangle is equal to

$A=bh$

In this problem we have

$A=5,000\ ft^{2}$

so

$5,000=bh$ -----> equation A

$b=\frac{h}{2}$ -----> equation B

Substitute equation B in equation A

$5,000=(\frac{h}{2})h$

$10,000=h^{2}$

square root both sides

$h=100\ ft$

Find the value of b

$b=\frac{h}{2}$ -----> $b=\frac{100}{2}=50\ ft$

step 2

Find the length of fencing

The perimeter of a rectangle is equal to

$P=2(b+h)$

we have

$h=100\ ft$

$b=50\ ft$

substitute

$P=2(50+100)=300\ ft$

6 0

4 years ago