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3 years ago

5

Please help ive been trying and i just cant get it right

1 answer:

avanturin [10]3 years ago

5 0

The correct answer is c. :)

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10 in<br> Given the figure. Find AC.

rjkz [21]

Answer:

if its an arc and center angle is given it could be double the size. IF it is a triangle measure you would use Pythagoras for triangle and trig for given angle, if two triangles are shown and they are scale of each other alternative measures given divide into each measure by the correct line and check this with the matching angles. when found as a division this is the ratio so then you just multiply to find the larger measure but divide to find the smaller measure. AC could also be a junction or vector, if its a type of vector then you just follow the arrows and count how many arrows fit the line pick a direction and ie) if its x2 a then you show a+a.

Step-by-step explanation:

5 0

3 years ago

What is the product?<br> (-2x- 9y2 )(-4x-3)

lara [203]

Answer:

$36xy^2 + 8x^2 + 27y^2 + 6x$

Step-by-step explanation:

Use the FOIL method of multiplying binomials.

First term in each binomial: $-2x * -4x = 8x^2$

Outside terms: $-2x * -3 = 6x$

Inside terms: $-9y^2 * -4x = 36xy^2$

Last term in each binomial: $-9y^2 * -3 = 27y^2$

Now, rearrange the terms correctly. $36xy^2 + 8x^2 + 27y^2 + 6x$

This is our final answer, since it can not be simplified any more.

4 0

3 years ago

Can somebody help me? Thank you.

Lilit [14]

Supplementary angles

8 0

3 years ago

Read 2 more answers

A tank contains 200 liters of fluid in which 50 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pu

mel-nik [20]

At the start, the tank contains A(0) = 50 g of salt.

Salt flows in at a rate of

(1 g/L) * (5 L/min) = 5 g/min

and flows out at a rate of

(A(t)/200 g/L) * (5 L/min) = A(t)/40 g/min

so that the amount of salt in the tank at time t changes according to

A'(t) = 5 - A(t)/40

Solve the ODE for A(t):

A'(t) + A(t)/40 = 5

e^(t/40) A'(t) + e^(t/40)/40 A(t) = 5e^(t/40)

(e^(t/40) A(t))' = 5e^(t/40)

e^(t/40) A(t) = 200e^(t/40) + C

A(t) = 200 + Ce^(-t/40)

Given that A(0) = 50, we find

50 = 200 + C ==> C = -150

so that the amount of salt in the tank at time t is

A(t) = 200 - 150 e^(-t/40)

7 0

3 years ago

Find the new amount 2000 miles increased by 33%

Goryan [66]

Answer:

$2,660\ miles$

Step-by-step explanation:

we know that

The amount of 2,000 miles represent 100%

If the amount is increased by 33%

then

The new percent of the amount will be

100%+33%=133%

so

using proportion

$\frac{2,000}{100\%}=\frac{x}{133\%}\\\\x=2,000(133)/100\\\\x=2,660\ miles$

3 0

3 years ago