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Tpy6a [65]
3 years ago
5

Please help ive been trying and i just cant get it right

Mathematics
1 answer:
avanturin [10]3 years ago
5 0
The correct answer is c. :)
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w=\begin{cases}3^{1/8}2^{1/16}e^{i3\pi/32}&\text{for }k=0\\\\3^{1/8}2^{1/16}e^{i11\pi/32}&\text{for }k=1\\\\3^{1/8}2^{1/16}e^{i19\pi/32}&\text{for }k=2\\\\3^{1/8}2^{1/16}e^{i27\pi/32}&\text{for }k=3\\\\3^{1/8}2^{1/16}e^{i35\pi/32}&\text{for }k=4\\\\3^{1/8}2^{1/16}e^{i43\pi/32}&\text{for }k=5\\\\3^{1/8}2^{1/16}e^{i51\pi/32}&\text{for }k=6\\\\3^{1/8}2^{1/16}e^{i59\pi/32}&\text{for }k=7\end{cases}
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