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denis-greek [22]
3 years ago
9

Show how to make one addend the next tens number. Complete the new addition sentence. 26+27=?

Mathematics
1 answer:
Usimov [2.4K]3 years ago
3 0
26 plus 27 is 53
hope I helped
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Can anyone help me please, I will mark brainliest to the right answer
adoni [48]

Answer:

A

Step-by-step explanation:

First 4 sets of (x, y) show that when x increases 2, y increases 3. It seems the relationship is linear. But last 2 set show that x increases 1, y increases 3. So the relation is NOT linear

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The square of the sum of 7 times x and 3 divided by 4 times the difference of x and 1
4vir4ik [10]
I believe the 3rd answer down if the information you provided is correct

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then 4 times the difference.  so I believe 4 (x-1) on the bottom.
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What is the rate of increase for the function f(x) = {(124)2X ?
Drupady [299]

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Step-by-step explanation:

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3 years ago
Prove that if {x1x2.......xk}isany
Radda [10]

Answer:

See the proof below.

Step-by-step explanation:

What we need to proof is this: "Assuming X a vector space over a scalar field C. Let X= {x1,x2,....,xn} a set of vectors in X, where n\geq 2. If the set X is linearly dependent if and only if at least one of the vectors in X can be written as a linear combination of the other vectors"

Proof

Since we have a if and only if w need to proof the statement on the two possible ways.

If X is linearly dependent, then a vector is a linear combination

We suppose the set X= (x_1, x_2,....,x_n) is linearly dependent, so then by definition we have scalars c_1,c_2,....,c_n in C such that:

c_1 x_1 +c_2 x_2 +.....+c_n x_n =0

And not all the scalars c_1,c_2,....,c_n are equal to 0.

Since at least one constant is non zero we can assume for example that c_1 \neq 0, and we have this:

c_1 v_1 = -c_2 v_2 -c_3 v_3 -.... -c_n v_n

We can divide by c1 since we assume that c_1 \neq 0 and we have this:

v_1= -\frac{c_2}{c_1} v_2 -\frac{c_3}{c_1} v_3 - .....- \frac{c_n}{c_1} v_n

And as we can see the vector v_1 can be written a a linear combination of the remaining vectors v_2,v_3,...,v_n. We select v1 but we can select any vector and we get the same result.

If a vector is a linear combination, then X is linearly dependent

We assume on this case that X is a linear combination of the remaining vectors, as on the last part we can assume that we select v_1 and we have this:

v_1 = c_2 v_2 + c_3 v_3 +...+c_n v_n

For scalars defined c_2,c_3,...,c_n in C. So then we have this:

v_1 -c_2 v_2 -c_3 v_3 - ....-c_n v_n =0

So then we can conclude that the set X is linearly dependent.

And that complet the proof for this case.

5 0
3 years ago
Mari spends $6 on cheese for a party she also plans to buy b boxes of crackers that cost $3 per box
PSYCHO15rus [73]

Answer:

The answer is 6+3b<or equal to 15

Step-by-step explanation:

3 0
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