Answer: D) 8-------------------------
The number outside the (n-1) term, which is 8, is the common difference. It tells us how much to increment by each time. In this case, the next term is found by adding 8 onto the previous term. That's exactly what
is saying.
The answer to the question is a=3
<span>x in (-oo:+oo)</span><span>
(1/3)*((6/5)*x-3) = 0</span><span>
1/3*(6/5*x-3) = 0</span><span>
( 1/3 )</span><span>
1/3 = 0</span><span>
x belongs to the empty set</span><span>
( 6/5*x-3 )</span><span>
6/5*x-3 = 0 // + 3</span><span>
6/5*x = 3 // : 6/5</span><span>
x = 3/6/5</span><span>
x = 5/2</span><span>
x = 5/2</span>
Answer:
9
Step-by-step explanation:
Compare your x2 + y2=81 to the following:
x^2 + y^2 = 81
The " ^ " symbol indicates exponentiation.
Now compare x^2 + y^2 = 81 to
x^2 + y^2 = r^2.
This is the standard equation of a circle of radius r centered at the origin, (0,0). You can see for yourself that 81 must equal r^2.
Taking the square root of 81, we get plus or minus 9.
But the radius must be positive, so we reject the -9 and take +9.
The radius is 9.
