Using trigonometric identities, sin^2(y) = 1 - cos^2(y).
If you substitute that in, you get 1- cos^2(y)/(1-cos(y)).
You can factorise 1 - cos^2(y) to be (1-cos(y))(1+cos(y)).
This means that the answer is 1 + cos(y) as the 1 - cos(y) will cancel.
Answer:
The scale factor of the sides of the Octagon is 2:5
Step-by-step explanation:
Both these octagons can be considered as the combination of 8 similar triangles joined edge to edge.
We know this property of similar triangles, that the ratio of area of similar triangles is proportion to the square of the ratio of sides of the similar triangle.

From the above property, we plug in the values


Therefore, the ratio of the sides of the Octagon are 2:5.
A^2b^2 + 3ab + 3ab + 3^2
= a^2b^2 + 6ab + 9
We know that
The sum of the lengths of any two sides of a triangle
must be greater than the length of the third side.
therefore
(3+3/4)=3.75 in
the third side must be < 3.75 in
the length could be 3 in
Answer:
-13.4+2.3c
Step-by-step explanation:
Add the like terms.
-6.5-5.1-1.8=-13.4
-13.4+2.3c
Hope this helps!
If not, I am sorry.