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coldgirl [10]
3 years ago
12

Use completing the square to solve for x in the equation (c+7)(x-9)=25

Mathematics
1 answer:
trasher [3.6K]3 years ago
6 0
I don’t know sorry about that
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Esteban wants to take out a $5,000 loan from the bank and is offered two choices. If he pays the loan back within 3 years, he wi
castortr0y [4]

Answer:

ESTEBAN IS FOKING BROKE

Step-by-step explanation:

8 0
3 years ago
Which expression can be used to find the price of a $400 telescope after a 32% markup? Select all that apply.
elena-s [515]
<h3>There are 2 answers: choice C, choice D</h3>

====================================================

Explanation:

32% = 32/100 = 0.32

32% of 400 = 0.32*400 = 400(0.32), which adds onto the original 400 to get 400+400(0.32). This is why choice D is one of the answers.

We can factor out the GCF 400 to go from 400+400(0.32) to 400(1+0.32) which then simplifies to 400(1.32) or just 400*1.32. This shows choice C is the other answer. Using a calculator,

400+400(0.32) = 400 + 128 = 528

400*1.32 = 528

meaning that 400+400(0.32) = 400*1.32

The other answer choices result in other values, showing that they aren't equivalent to 528.

6 0
3 years ago
The coordinates of the vertices of triangle ABC are A(-1,3), B(1,2) and C(-3,-1).
Romashka [77]
In order to prove the triangle is a right angled triangle we need to prove that the slope of the lines CA and BC  and AB have any  negative reciprocals.Lets find the slopes . 
AB=(-1,3), (1,2) slope of AB = 2-3/1-(-1)= -1/2 slope of AB is -1/2
BC = (1,2), (-3,1) slope of BC is 1-2/-3-1= -1/-4 slope of BC is 1/4
Slope of CA =(-3,1)(-1,3) slope of 3-1/-1-(-3)=-2/-2=1

Since the slopes do not have any negative reciprocals so the triangle is not a right angled triangle 
5 0
3 years ago
Please help!
crimeas [40]

Answer:

The zeros are:

x =4, x=2, x = 5

  • The function has three distinct real zeros.

Hence, option (B) is true.

Step-by-step explanation:

Given the expression

h\left(x\right)=\left(x-4\right)^2\left(x^2-7x+\:10\right)

Let us determine the zeros of the function by putting h(x) = 0 and solving the expression

0=\left(x-4\right)^2\left(x^2-7x+10\right)

switch sides

\left(x-4\right)^2\left(x^2-7x+10\right)=0

as

x^2-7x+\:10=\left(x-2\right)\left(x-5\right)

so

\left(x-4\right)^2\left(x-2\right)\left(x-5\right)=0

Using the zero factor principle

  • \mathrm{If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

so

x-4=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0

x =4, x=2, x = 5

Thus, the zeros are:

x =4, x=2, x = 5

It is clear that there are three zeros and all the zeros are distinct real numbers.

Therefore,

  • The function has three distinct real zeros.

Hence, option (B) is true.

4 0
3 years ago
Solve for x and y in the parallelogram
Lubov Fominskaja [6]

Answer:

x=3

y=6

Step-by-step explanation:

Hope this helps! :)

4 0
3 years ago
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