Sub those points for x
f(x) is the y
(x,y)
so for x=0
f(0)=2(0)^4+3
f(0)=0+3
f(0)=3
(0,3) is a opint
for x=1
f(1)=2(1)^4+3
f(1)=2(1)+3
f(1)=2+3
f(1)=5
(1,5) is another point
for x=2
f(2)=2(2^4)+3
f(2)=2(16)+3
f(2)=32+3
f(2)=35
(2,35) is another point
points are
(0,3)
(1,5)
(2,35)
Answer:
<u><em>Yes.</em></u>
Step-by-step explanation:
<em>To find the answer we will put it into the equation, since</em><em><u> x = 1 and y = 2</u></em><em> we will write it like this, </em><u><em>6(1) - 2 > 3.</em></u><em> Since </em><u><em>6 x 1 = 6</em></u><em>, we will now </em><u><em>subtract 6 from 2 which equals 4</em></u><em>. Therefore, the equation is </em><u><em>correct because 4 is bigger than 3.</em></u>
Answer:
1. x = 2√3 or 3.46
2. y = 4√3 or 6.93
3. z = 4√6 or 9.80
Step-by-step explanation:
1. Determination of the value of x.
Angle (θ) = 60°
Opposite = 6
Adjacent = x
Tan θ = Opposite /Adjacent
Tan 60 = 6 / x
√3 = 6/x
Cross multiply
x√3 = 6
Divide both side by √3
x = 6 / √3
Rationalise
x = (6 / √3) × (√3/√3)
x = 6√3 / 3
x = 2√3 or 3.46
2. Determination of the value of y.
Angle (θ) = 60°
Opposite = 6
Hypothenus = y
Sine θ = Opposite /Hypothenus
Sine 60 = 6/y
√3/2 = 6/y
Cross multiply
y√3 = 2 × 6
y√3 = 12
Divide both side by √3
y = 12/√3
Rationalise
y = (12 / √3) × (√3/√3)
y = 12√3 / 3
y = 4√3 or 6.93
3. Determination of the value of z.
Angle (θ) = 45°
Opposite = y = 4√3
Hypothenus = z
Sine θ = Opposite /Hypothenus
Sine 45 = 4√3 / z
1/√2 = 4√3 / z
Cross multiply
z = √2 × 4√3
z = 4√6 or 9.80